SIDDANNA MARPALLE. Govt. Neelambika PU College Basavakalyan Dist : Bidar. Q: 1. The lowest first ionisation energy would be associated with which of the following structures? a] 1s 2 2s 2 2p 6 3s 1 b] 1s 2 2s 2 2p 5 c] 1s 2 2s 2 2p 6 d] 1s 2 2s 2 2p 6 3s 2 3p 2.
Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.
Govt. Neelambika PU College Basavakalyan
Dist : Bidar
Q: 1. The lowest first ionisation energy would be associated with which of the following structures?
a] 1s2 2s2 2p6 3s1
b] 1s2 2s2 2p5
c] 1s2 2s2 2p6
d] 1s2 2s2 2p6 3s2 3p2
Ans : a] 1s22s2 2p6 3s1
Q: 2. Which of the following combinations contains only isoelectronic species?
a] N3-, O2-, Cl-
b] F-, Ar, S2-, Cl-
c] P3-,S2-, Cl-
d] N3-, F-, O2-, Ar
Ans: c] P3-,S2- ,Cl-
Q: 3. Fluorine has unexpectedly lower electronic affinity than that of chlorine due to.
a] Big size of fluorine, which results in increase in the electron-electron repulsion 2P subshell
b] Small size of fluorine, which results in increase in the electron-electron repulsion 2p-subshell.
c] Decrease in electron-electron repulsion
d] No electron-electron repulsion in 2p- subshell
Ans: b] Small size of fluorine, which results in
increase in the electron-electron
Ans: d] Fluorine
Ans: d] Ca2+
a] effective nuclear charge increases
b] Atomic mass increases.
c] Additive elements are accommodated in new electron level.
d] Atomic number increases.
Ans: c] Additive elements are accommodated in
new electron level.
Q: 7. Electrons which are characterised by the outer shell configuration ns1 to ns2 np6 are collectively called.
a) transition elements.
b) representative element .
d) inner transition elements
Ans: b) representative element .
Q:8. Atomic numbers of V,Cr, Mn and Fe are 23,24,25and 26 respectively, which one of these may have the highest second
Ans:- d) Cr
E.c- of Cr – 3d5 ,4s1, as 3d- orbital is exactly half filled, removal of election is difficult.
a) all elements with their diagonally opposite elements.
b) all elements of 3rd and 4th periods
c) some elements of 2nd and 3rd periods.
d) elements of d-block.
Ans: c) some elements of 2nd and 3rd periods.
Q :10. Lithium is not stored in kerosene. It is kept wrapped in paraffin wax because
a) it reacts with kerosene .
b) Lithium floats over kerosene as its density is low
c) Lithium is a soft metal.
d) Lithium sinks in kerosene
Ans : b) Lithium floats over kerosene as its density is low .
Q : 11. compounds of group 2 elements are less soluble in water than the corresponding alkali metal salts due to
a) their high ionisation energy
b) their high lattice energy
c) less basic character
d) low electronegativity values.
Ans : b) their high lattice energy
a) Nuclear charge of “Ca” is more than “Mg”
b) Size of “Ca” is less than “Mg”
c) Vacant 3d orbital of “Ca”
d) completely filled 3d orbital’s .
Ans: c) Vacant 3d orbital of “Ca”
leads to the much increasing atomic
volume hence density decreases
configuration is 1s22s22p63s1 is
Ans: a) Basic
a) 12 five membered and 20- six membered rings
b) 12 five membered and 20- five membered rings
c) Same no of five and six membered rings
d) No five and six membered rings
Ans: a) 12 five membered and 20- six memberd
1368 KHz, what is the wavelength of electromagnetic radiation emitted by transmitter
Ans: b) 219.3m
= 3 x 108
1368 x 103
= 219.3 m
a) 495 x 10-19J
b) 4.95 x 10-18J
c) 4.95 x 10-19J
d) 495 x 10-18J
Ans: c) 4.95 x 10-19J
E = h
= 6.6 x 10-34 x 3 x 108
400 x 10-10
E = 4.95 x 10-19J
electron moving with a velocity of
a) 6.068 x 10-9m
b) 3.133 x 10-37m
c) 6.626 x 10-9 m
d) 6.018 x 10-7 m
Ans: A) 6.068 x 10-9 m
m = 9.1 x 10-31 Kg
c = 1.2 x 105 m/s
of an element are given below
n = 2, l = 0, m = 0, s = + 1/2 , The atom is
Ans: a) Lithium
numbers is not possible
n l m s
a) 3 2 -1 0
b) 3 2 -1 + ½
c) 3 2 1 + ½
d) 3 2 1 - ½
Ans: a) n=3 l=2 m=-1 s=0
with mass 70 is
Ans b) 40
A = 70, z = 30
n = A-z
A] + ½ h/2π
C] √2 h/2π
Ans: d] Zero
Orbital angular momentum = l h/2π
For ‘S’ orbital l=0
0 x h/2π = 0
when an electron jumps fro n =3 to n= 1 in a
hydrogen atom (R=107/m)
a) 1.11 x 108/m b) 8.9 x 108/m
c) 8.9 x 106/md) 8.9 x 107/m
Ans: c) 8.9 x 106/m
Ans : CN-
No of electrons in co = 6+8 = 14
In CN- 6+7+1 = 14
the position and momentum of a small particle
with absolute accuracy, This is stated by
Ans : c) Heisenberg
a) 4s has more energy than 3d
b) 4s has same energy energy as that 3d
c) ( n + 1 ) Value for 4s is more than 3d
d) ( n + 1 ) Value for 4s is less than 3d
Ans: d) ( n + 1 ) Value for 4s is less than 3d