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Propagation of uncertaintiesPowerPoint Presentation

Propagation of uncertainties

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### Propagation of uncertainties

Formulas and graphs

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Volume of a cylinderD = 2.9 cm

D = 0.05 cm+ 0.01 cm+ 0.1 cm

h = 1.5 cm

h = 0.05 cm+ 0.01 cm+ 0.05 cm

D = (2.9 ± 0.16) cm

h = (1.5 ± 0.11) cm

Volume of a cylinder

D = (2.9 ± 0.16) cm

h = (1.5 ± 0.11) cm

Result will have 2 significant figures

V = ¼ p D2 h

V = ¼ p (2.9 cm)2 1.5cm

V = 9.907789463 cm3

V = 9.9 cm3

How sure can we be about the result?

Lowest end: D=2.74 cm, h= 1.39cm V = 8.2 cm3 (-17%)

Highest end: D=3.06 cm, h= 1.61cm V = 11.8 cm3 (+19 %)

- Using physical quantities with uncertainty in a formula leads to calculation results with an uncertainty.
- How much uncertainty?
- How does the formula influence this uncertainty?
- Is there a way to predict this?

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Uncertainties and functionsV = ¼ p D2 h

V

V

Uncertainty in volume

arising from uncertainty

in diameter:

D-D

D+D

D

D

Propagation of uncertainty

V = ¼ p D2 h

Uncertainty in V = contribution from D + contribution from h

Every regular equation has an error equation.

Every error equation has one term for each measured quantity.

Volume of a cylinder

D = (2.9 ± 0.16) cm

h = (1.5 ± 0.11) cm

V = 9.9 cm3

V = (9.9 ± 1.9) cm3

Relative error: V/V 100% = 1.9/9.9 100% = 19%

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