4 3 matrices and determinants
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4.3 Matrices and Determinants. Algebra 2 Mrs. Spitz Fall 2006. Objectives:. Evaluate the determinant of a 3 x 3 matrix, and Find the area of a triangle given the coordinates of its vertices. Assignment. pp. 170-171 #5-26 all. Determinants.

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4.3 Matrices and Determinants

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4 3 matrices and determinants

4.3 Matrices and Determinants

Algebra 2

Mrs. Spitz

Fall 2006


Objectives

Objectives:

  • Evaluate the determinant of a 3 x 3 matrix, and

  • Find the area of a triangle given the coordinates of its vertices.


Assignment

Assignment

  • pp. 170-171 #5-26 all


Determinants

Determinants

  • Every square matrix has a determinant. The determinant has the same elements as the matrix, but they are enclosed between vertical bars instead of brackets. In Chapter 3, you learned a method for evaluating a 2 x 2 determinant.


Determinants1

Determinants

  • The determinant of

    is . To evaluate

    The determinant, use the rule for second order determinants.


Expansion by minors

Expansion by Minors

  • A method called expansion by minors can be used to evaluate the determinant of a 3 x 3 matrix. The minor of an element is the determinant formed when the row and column containing that element are deleted. For the determinant


Expansion by minors1

Expansion by Minors

  • To use expansion by minors with third-order determinants, each member of one row is multiplied by its minor. The signs of the products alternate, beginning with the second product. The definition below shows an expansion using the elements in the first for of the determinant. However, ANY row can be used.

Expansion of a Third-Order Determinant


4 3 matrices and determinants

Ex. 1: Evaluate the determinant of

Using expansion by minors.


Using diagonals

Using Diagonals

  • Another method for evaluating a third order determinant is using diagonals.

  • STEP 1: You begin by repeating the first two columns on the right side of the determinant.


Using diagonals1

Using Diagonals

  • STEP 2: Draw a diagonal from each element in the top row diagonally downward. Find the product of the numbers on each diagonal.

aei

bfg

cdh


Using diagonals2

Using Diagonals

  • STEP 3: Then draw a diagonal from each element in the bottom row diagonally upward. Find the product of the numbers on each .

gec

hfa

idb


Using diagonals3

Using Diagonals

  • To find the value of the determinant, add the products in the first set of diagonals, and then subtract the products from the second set of diagonals.

    The value is:

    aei + bfg + cdh– gec – hfa – idb


4 3 matrices and determinants

First, rewrite the first two columns along side the determinant.

Ex. 2: Evaluate using diagonals.


4 3 matrices and determinants

Next, find the values using the diagonals.

0

-5

24

Ex. 2: Evaluate using diagonals.

4

60

0

Now add the bottom products and subtract the top products.

4 + 60 + 0– 0 – (-5) – 24 = 45. The value of the determinant is 45.


Area of a triangle

Area of a triangle

  • Determinants can be used to find the area of a triangle when you know the coordinates of the three vertices. The area of a triangle whose vertices have coordinates (a, b), (c, d), (e, f) can be found by using the formula:

and then finding |A|, since the area cannot be negative.


4 3 matrices and determinants

Ex. 3: Find the area of the triangle whose vertices

have coordinates (-4, -1), (3, 2), (4, 6).

How to start: Assign values to a, b, c, d, e, and f and substitute them into the area formula and evaluate.

a = -4, b = -1, c = 3, d = 2, e = 4, f = 6

8

-24

-3

18

-8

-4

Now add the bottom products and subtract the top products.

-8 + (-4) + 18– 8 – (-24) –(-3) = 25. The value of the determinant is 25. Applied to the area formula ½ (25) = 12.5. The area of the triangle is 12.5 square units.


4 3 matrices and determinants

Sometimes one or more of the elements of a determinant may be unknown, but the value of the determinant is known. You can use expansion to find the values of the variable.

Ex. 4: Solve for n if

24n – 84 – 36n + 48n +84n – 18 = -582

120n – 102 = -582

120n = -480

n = -4

The value of n is -4.

Collect like terms

Add 102 to both sides

Divide by 120 both sides.


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