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Chapter 15 - Chemical Equilibrium USING THE EQUILIBRIUM CONSTANT

Chapter 15 - Chemical Equilibrium USING THE EQUILIBRIUM CONSTANT 1. Which is favored - Reactants or products? 2. Predict direction of a reaction Q  reaction quotient 3. Obtaining equilibrium concentrations of reactants and products. 4. Predict effect of changing conditions -

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Chapter 15 - Chemical Equilibrium USING THE EQUILIBRIUM CONSTANT

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  1. Chapter 15 - Chemical Equilibrium USING THE EQUILIBRIUM CONSTANT 1. Which is favored - Reactants or products? 2. Predict direction of a reaction Q  reaction quotient 3. Obtaining equilibrium concentrations of reactants and products. 4. Predict effect of changing conditions - Le Chatelier’s Principle

  2. Concept of Equilbrium • In chemical equilibria, forward and reverse reactions occur at equal rates. • A B • At equilibrium, forward rate = backward rate • Forward reaction A B • Rate = kf [A] • Backward reaction B  A • Rate = kb [B] • At equilibrium, kf [A] = kb [B] • Dynamic balance • Reaching equilibrium may be slow!

  3. Haber process: N2(g) + 3H2(g)2NH3(g) • Initial State: reactants onlyInitial state: products only • Same equilibrium achieved • Time  Time  • Final State: ratio of products to reactants is the same for both! • The relationship between the concentrations of products and reactants at “equilibrium” will be the same regardless of starting conditions. • Catalysts do not effect equilibrium concentrations H2 H2 NH3 NH3 N2 N2

  4. Equilibrium Constant Equilibrium point of any reaction is characterized by a single number. Example: 2A B (2NO N2O4) For this reaction: the ratio of concentrations at equilibrium will be constant. Keqis aNUMBER. Keq(the number) DOES NOT depend on concentration It’s a function of temperature only. constant

  5. N2(g) + 3H2(g) 2NH3(g) • What is the equilibrium constant expression for the Haber process? • 1. • 2. • 3. 4. 5.

  6. Predicting the direction of a reaction • aA + bB cC + dD • Reaction quotient Q • Note: the concentrations used are NOT equilibrium concentrations. • When Q = Kcsystem IS at equilibrium • When Q < Kcreaction moves to right • (produces product) • When Q > Kcreaction moves to left

  7. General Approach to Equilibrium Constant Problems • Write the balanced reaction. • Write the general form for Keq. • Set up a data table: (may need algebraic unknowns) initial conditions changes in concentrations equilibrium concentrations 4) Substitute equilibrium concentrations into the expression for Keq and solve.

  8. Example: 2 IBr(g) Br2(g) + I2(g) Initially [IBr] = [I2] = [Br2] = 0.05M What is the value of Q? Which way does reaction go? What are the final concentrations of reactants and products?

  9. A 1.0 L container holds 224 g of Fe and 5.00 mole of H2O(l). It is heated to 1000K and reaches equilibrium. 56 g of Fe are left unreacted. What is Kc at 1000K? 3Fe(s) + 4H2O(g) Fe3O4(s) + 4H2(g) initial change final

  10. Le Chatelier’s Principle • If a system at equilibrium is disturbed by changing • Concentration of one of the components • Temperature • Pressure • the concentrations will shift to counteract the disturbance. • Fe3+(aq) + SCN-(aq) [Fe(SCN)]2+(aq) • yellow colorlessred • heat + CaCO3 (s) CaO(s) + CO2 (g)

  11. 2HI(g) H2(g) + I2(g) • If the system is at equilibrium and we add 0.1 mole of HI, • what will happen? • 1. reaction shifts to right  • 2. reaction shifts to left  • 3. no change occurs • If the volume of the container decreases, what will happen? • 1. reaction shifts to right  • 2. reaction shifts to left  • 3. no change occurs

  12. Summary: • changing concentration (or V so that [ ] changes) puts a stress on the system. • Stresses do not change Keq! • Q changes; system shifts to re-establish equilibrium • QK • WHAT IF TEMPERATURE CHANGES? Keq changes • change depends on whether the reaction • is exothermic or endothermic. •  • H+H

  13. Nitrogen fixation Must break N-N triple bond (D = 946 kJ) Important in biological systems (proteins, nucleic acids) & industrially (fertilizer, polymers, explosives, …) Beans, bacteria, etc: nitrogenase enzyme reduces N2 to NH3 at room temp, 1 atm pressure Fritz Haber (a German…) developed the process for fixing N2 in 1912. World War I: Germany imported nitrates from Chile to make explosives. Allied blockade prevented these compounds from reaching Germany. Haber process was used to maintain soluble nitrogen supplies.

  14. Haber process - Industrial process used to make ammonia • N2(g) + 3H2(g)2NH3(g) + heat

  15. N2(g) + 3H2(g)2NH3(g) + heat Do we want high or low temperature? Do we want high or low pressure? Liquefy ammonia as process proceeds.WHY? Problem:rate of reaction increases as T increases, BUT equilibrium constant decreases at higher T.

  16. CAN’T change the equilibrium constant so doing the reaction at very high temperature would never work. Solution: need to find a way to speed up the reaction at lower temperature: Need an appropriate catalyst. Haber process: uses Fe/Al2O3 catalyst works a 400-500oC, at pressures of 200-600 atm At T < 400oC, lower pressures could be used to get same equilibrium conversion of N2 to NH3 However, the rate falls exponentially with decreasing temperature Still an enormous research problem: Fertilizer H2 storage (NH3 is 17.6% hydrogen) Polymer chemistry

  17. ROLE OF CATALYST A catalyst increases the rate at which equilibrium is achieved, but does not change the composition the equilibrium mixture. It increases the rate by lowering the activation barrier between reactants and products Ea is lowered the same amount for BOTH forward and backward reactions SO the rate for BOTH reactions is increased. The value of the equilibrium constant is NOT affected by the presence of a catalyst

  18. Catalytic converter N2(g) + O2(g) 2NO(g) H = +180.8kJ Keq at 300K = 10-15 What happens if T is increased? At 2400K, Keq = 0.05 At high T (combustion T), NO is favored. As gases cool, equilibrium favors NO conversion to N2 and O2, BUT low T means rate is slow: need a catalyst: Pt, Rh, Pd In catalytic converter, NO is reduced fast (~100-400x in 10-3 s)

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