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Acceleration - PowerPoint PPT Presentation

Acceleration. GW. 運動力學. 直線運動 F = ma [ N = kg × m/sec 2 ] 旋轉運動 T = Iω [ Kg-m = Kg-m-sec 2 × rad/sec 2 ]. 等加速度運動. V 0 : 初速度 V : 末速度 a : 加速度 t : 經歷時間 S : 位移 (1) V = V 0 + at (2) S = V 0 t + ½ at 2

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Acceleration

GW

F = ma [ N = kg × m/sec2 ]

T = Iω [ Kg-m = Kg-m-sec2 × rad/sec2 ]

V0 : 初速度 V : 末速度 a : 加速度

t : 經歷時間 S : 位移

(1) V = V0 + at

(2) S = V0t + ½ at2

(3) V2 = V02 + 2aS

GD2與慣性矩的關係

m = G/g k = D/2

I = mk2 = ( G/g ) × ( D/2 )2 = GD2 / 4g

GD2 = 4 g I

( 動能 ) E = ½ W/G v2

E = ½ × GDP2 /4g × ( 2πn/60 )2

Ta = Iω , ω = Ta/I = 4g/GD2 × Ta

= (GD2/375)(a/π/D)

Torque : 馬達所需之扭矩

Ta : 機構之加速扭矩

S : 齒輪組之減速比

η : 機械效率

F’ : 機構摩擦力

Ta’ : 爬坡阻力 = ½ DW sin θ

D : 皮帶輪直徑

θ : 爬坡角度

Torque = [ Ta × S × ( 1/η )] + F’ + Ta’

Parabolic Curve ( 拋物線 )

y : 速度 ( PPS ) x : 時間 ( sec )

y = ax2 + bx + c ( a , b , c 為常數 )

1. 掃描器對於加速部分有越來越快的需求 .

2. 加速度的計算有助於分析加速方面的問題 .

3. 相同的掃描步數下 , 馬達步進角越小 , 齒輪比

4. Carriage越重 , 加速距離越短對於加速越不利 .