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Empirical Formulas

Empirical Formulas. Empirical formula – lowest whole-number ratio of the elements in a compound (divide by – Greatest Common Factor) What is the empirical formula of C 2 N 2 H 8 CNH 4. Empirical Formula Calculations 1.) Change the given information to moles for each element.

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Empirical Formulas

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  1. Empirical Formulas

  2. Empirical formula – • lowest whole-number ratio of the elements in a compound • (divide by – Greatest Common Factor) • What is the empirical formula of C2N2H8 • CNH4

  3. Empirical Formula Calculations • 1.) Change the given information to moles for each element. • 2.) Divide each mole answer by the smallest number of moles. • 3.) If the answers from step 2 are not whole numbers then divide by the smallest decimal part. • 4.) Write the formula with the mole ratio as subscripts.

  4. EX 1 Find the empirical formula. • A compound contains 9.31g of Ag and 0.69g of O.

  5. Ag2O

  6. EX 2 A compound contains 25.9% N and 74.1% O. • Find the empirical formula.

  7. Nitrogen = 1 ÷ 0.5 = 2 • Oxygen = 2.5 ÷ 0.5 = 5 N2O5

  8. MOLECULAR FORMULAS

  9. Molecular formula – empirical formula or its multiple • Several compounds can have the same empirical formula but different molecular formulas. • What is the empirical formula of C2N2H8? • CNH4 • What is the molecular formula of CNH4? • C2N2H8

  10. Convert molecular  empirical • Divide subscripts by greatest common factor • Convert empirical  molecular • multiply subscripts by …

  11. EX 1 • The empirical formula is CH4N and the molar mass is 60.0 g. Find the molecular formula. • C 1 X 12.0 = 12.0g • 4H 4 X 1.0 = 4.0g • N 1 X 14.0 = 14.0g • 30.0g C2H8N2

  12. EX 2 • Find the molecular formula of C4H6O if the molar mass is 280.0g. • 4C 1 X 12.0 = 48.0g • 6H 4 X 1.0 = 6.0g • O 1 X 14.0 = 16.0g • 70.0g C16H24O4

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