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The correct set up for a heterozygous dihybrid cross isPowerPoint Presentation

The correct set up for a heterozygous dihybrid cross is

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1. Which is the correct set up for a dihybrid cross of two heterozygous parents RrYyx RrYy?See following slides:

The correct set up for a heterozygous dihybrid cross is

- A
- B
- C

- Each side of a Punnett Square represents all the possible alleles in a gamete from each parent.
- Parent gametes always contain one allele for each gene. (one R or r and one Y or y in this case).
- Four possible combinations of the alleles for the two genes are possible- RY, Ry, rYand ry.

2. For the Punnett square of RrYyx RrYy, what phenotype ratio would be expected in the offspring?

- 1:1:1:1
- 9:3:3:1
- 3:1
- 1:2:1

Dominant for both : Dom 1st/Rec. 2nd : Rec for 1st/Dom. for 2nd: Recessive for both

9 : 3 : 3 : 1

3. The 9:3:3:1 ratio for a heterozygous dihybrid cross will apply if

- the traits are on separate chromosomes
- the traits are closely linked on the same chromosome
- Either A or B
- Neither A nor B

A dihybridPunnett square assumes that all 4 gamete combinations are equally likely.

This will occur if the two genes are on different chromosomes. Independent assortment will make all 4 combinations equally likely.

When two genes are on the same chromosome, genetic recombination can occur due to crossing over.

However, if the two genes are close together on the chromosome, the recombinants will not be equally like as the original combination.

4. Determine the phenotype ratio for a cross between recombination can occur due to crossing over.GgHh and gghh.

- 9:3:3:1
- 1:1:1:1
- 3:1:3:1
- 1:2:1
- 3:1

Don’t need to fill out additional rows. recombination can occur due to crossing over.

All gametes of gghh will be gh.

Ratio of 1:1: 1:1

25% chance dominant phenotype for both traits

25% chance dominant for G, recessive for h

25% chance recessive for g, dominant for H

25% chance recessive for both

- C recombination can occur due to crossing over.
- B
- A
- B

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