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Relation

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Def: A relation is any set of ordered pairs.

Ex) { ( 2, 3), ( 4, -3), ( 5, 9), ( 3, 2) }

Def: The Domain (Input) of a relation is the set of all x values. D = { 2, 4, 5, 3 }

Def: The Range (Output) of a relation is the set of all y values. R = { 3, - 3, 9, 2 }

Def: A Function is a relation in which each value in the domain gives ( Corresponds to) only one value in the range.

Ex) { ( 3, 2), ( 5, 4), ( 9, 11), ( 5, 20) }

Not a Function.

x = 5 corresponds to y = 4 and y = 20.

Ex) { ( 2, 3), ( 4, -3), ( 5, 9), ( 3, 2) }

Yes, the relation is a function.

Ex) { ( -4,5), ( 7, 11), ( 0, 1), ( 3, 5)}

Yes, the relation is a function.

Ex) { ( 3,0), (-1, 7), ( 6, 11), (-1, 2)}

No, the relation is not a function.

Domain: { -1, 3, 6} Range: { 0, 2,7, 11}

- Relation or Set of ordered pairs.
{ ( 1, 1), ( 2, 4), (3, 9), (0, 0 ), ( -1,1), ( 2,4),(-3, 9) }

2) Graph

3) Equations

Not all sets of ordered pairs, graphs or equations are functions. To be a function, the set of ordered pairs, graph or equation must satisfy the definition given earlier.

{ ( 1, 1), ( 2, 4), ( 3, 9), ( 4, 16)}

Can you write an equation that describes the relationship between the x and y values?

y = x²

If x = 5, then y = 5² = 25.

An ordered pair was created. ( 5, 25)

If x = -7, then y = ( -7)² = 49.

An ordered pair was created ( -7,49)

Ex ) { ( 1, 3), ( 2, 5), ( 3, 7), ( 4, 9)}

y = 2x + 1

Ex) { ( 7, 4), ( 8, 5), ( 9, 6), ( 10, 7)}

y = x - 3

We now use a new symbol to represent y, the range value.

We introduce the symbol y = f(x)

The symbol is read “ f of x”

f(x) means the y value that is created by using a specific x value as input.

The x inside the parentheses is the domain value.

The symbol f(x) is the range value.

The expression 2x + 1 tells us what we need to do to the domain value, in order to get our range value.

The entire symbol 2x + 1, represents a ______ value.

Using f(x) = x³ , evaluate

- f( 4)
Using f(x) = -3x – 2, evaluate

- f( -3)b) f( t )
Using f(x) = x², evaluate

- f(x – 3)b) f( x – h)
Using f(x) = x² - 2x, evaluate

a) f( x – h ) b) f( x ) c) f( x – h ) – f(x)

Let’s look at the equation x = y²

If this equation represents a function, then if we plug in a value for x, then it should produce only one value for y.

Let x = 4. This gives 4 = y² and so

y = 2 or y = -2

No, x = y² does not represent y as a function of x.

Ex) x² + y² = 25

Ex)

Ex

Ex)

The Difference Quotient for functions is defined to be

Evaluate the difference quotient for

- f(x) = 3x + 1
b) f(x) = x²

- f(x) = x² - 2x
d) f(x) = - 4x

- Answers:
- 3
- 2x+h
- 2x + h – 2
- d) - 4

If we have the function { ( 1, 5), ( 3, 7), (-2,0)}, then

Domain = { 1, 3, -2} and Range = { 5, 7, 0}

What would it mean if I asked you to find the domain for the function

To find the Domain for a function when it is written as an Equation, means to find all real x values that will produce real y values.

Let’s plug x values into the function and see what happens?

Consider the x values as Input and the y values as Output.

Ask yourself. What x values produce y values that are real?

These are the values we want to include in the domain.

Ask yourself. What x values produce y values that are not real?

These are the values we want to exclude from the domain.

Write the answer using interval notation.

- Dividing a number by zero, produces a nonreal y value.
For example: 7/0 = not real or undefined

- Taking the square root of a negative number.
For example: is the same as ?² = - 4

Find the domain for each function below. Write the answer using interval notation.

f(x) = 3x + 2

The relation is not a function.

{ ( 1,2), ( 3, -2), ( -1, 4), ( 1, -2)}

Let’s plot these points on the coordinate system. What do we notice?

The two points (1,2) and ( 1, -2) have the same x value but different y value. They lie on the same vertical line.

The relation is a function

{ (-3, 2), ( -2, 1), ( -1, -3), ( 0, 2), ( 1, 3),

(2,0), ( 3, -2) }

Let’s plot these points on a coordinate system. What do we notice?

This graph represents a function because you cannot find two points that lie on the same vertical line.

YES

NO

NO

YES

Domain [ -5, 4 ]

Range [ 1, 7]

Domain [ -4 , 3]

Range [ -3 , 0 ]

Domain

Range

Domain

Range

f(x) is called an even function. The graph is symmetric with respect to the y –axis.

Notice:

f(2) = f( -2) = 3

f(4) = f( -4) = 1

Lastly, to be an even function means that

f (x) = f( - x )

This function is an odd function. This means that the graph is symmetric with respect to the origin.

Notice:

f(2) = 3 and f( -2) = -3

f(5) = 2 and f( -5) = -2

In other words,

f( -2) = - f( 2) = - ( 3) = -3

f(- 5) = - f( 5) = -( 2) = -2

If a function is odd, this means

f(-x) = - f(x)

An x- intercept is a point where a graph crosses the x- axis.

All x – intercepts are points with y = 0

( - 3, 0) and ( 2, 0)

A y – intercept is a point where the graph crosses the y – axis.

All y – intercepts are points with x = 0.

( 0, 4)

increasing

decreasing

We say that f(x) is increasing on the interval ( -6, 0).

We say f(x) is decreasing on the interval ( 0, 4).

When determining intervals of increase or decrease, we read the graph from left to right. In other words, let the x values get larger.

Over which intervals(months) was the account increasing?

Jan, Feb, March

Over which intervals(months) was the account decreasing?

April, May, July and August

Over which month(s) was the account constant?

June

Find interval(s) where f(x) is increasing, decreasing or constant.

- f(x) is increasing on
- (-5, -1) or ( 4, 7)

b) f(x) is decreasing on

( -1, 4)

c) f(x) is never constant

Determine the intervals where f(x) is increasing, decreasing or constant.

Increasing on ( - , -5) or ( 5, )

Constant on ( -5, 5)

f(x) is never decreasing

The average rate of the change as x goes from o months to 5 months, says that if my money were to change by the same amount every month, it would change by $80 per month, in order to go from the original $100 to the final $500. It is the slope the secant line.

Find a) f( 3)b) f(0)

c) f(-5)d) f( 4)

Let’s say I have a program where I pay $50 if I talk between 0 and 100 minutes, inclusively.

If I talk pass 100 minutes, they charge 7 cents per minute, plus the $50 for the first 100 minutes.

Let x = number of minutes we talk on the phone for the month.