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Relation PowerPoint PPT Presentation


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Relation. Def: A relation is any set of ordered pairs. Ex) { ( 2, 3), ( 4, -3), ( 5, 9), ( 3, 2) } Def: The Domain (Input) of a relation is the set of all x values. D = { 2, 4, 5, 3 } Def: The Range (Output) of a relation is the set of all y values. R = { 3, - 3, 9, 2 } .

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Relation l.jpg

Relation

Def: A relation is any set of ordered pairs.

Ex) { ( 2, 3), ( 4, -3), ( 5, 9), ( 3, 2) }

Def: The Domain (Input) of a relation is the set of all x values. D = { 2, 4, 5, 3 }

Def: The Range (Output) of a relation is the set of all y values. R = { 3, - 3, 9, 2 }


Function l.jpg

Function

Def: A Function is a relation in which each value in the domain gives ( Corresponds to) only one value in the range.

Ex) { ( 3, 2), ( 5, 4), ( 9, 11), ( 5, 20) }

Not a Function.

x = 5 corresponds to y = 4 and y = 20.


Determine if the relation is a function l.jpg

Determine if the relation is a function.

Ex) { ( 2, 3), ( 4, -3), ( 5, 9), ( 3, 2) }

Yes, the relation is a function.

Ex) { ( -4,5), ( 7, 11), ( 0, 1), ( 3, 5)}

Yes, the relation is a function.

Ex) { ( 3,0), (-1, 7), ( 6, 11), (-1, 2)}

No, the relation is not a function.

Domain: { -1, 3, 6} Range: { 0, 2,7, 11}


Functions can be represented using l.jpg

Functions can be represented using:

  • Relation or Set of ordered pairs.

    { ( 1, 1), ( 2, 4), (3, 9), (0, 0 ), ( -1,1), ( 2,4),(-3, 9) }

    2) Graph

    3) Equations

    Not all sets of ordered pairs, graphs or equations are functions. To be a function, the set of ordered pairs, graph or equation must satisfy the definition given earlier.


Functions as equations l.jpg

Functions as Equations

{ ( 1, 1), ( 2, 4), ( 3, 9), ( 4, 16)}

Can you write an equation that describes the relationship between the x and y values?

y = x²

If x = 5, then y = 5² = 25.

An ordered pair was created. ( 5, 25)

If x = -7, then y = ( -7)² = 49.

An ordered pair was created ( -7,49)


Functions can have different relationships between the x and y l.jpg

Functions can have different relationships between the x and y

Ex ) { ( 1, 3), ( 2, 5), ( 3, 7), ( 4, 9)}

y = 2x + 1

Ex) { ( 7, 4), ( 8, 5), ( 9, 6), ( 10, 7)}

y = x - 3


Function notation l.jpg

Function Notation

We now use a new symbol to represent y, the range value.

We introduce the symbol y = f(x)

The symbol is read “ f of x”

f(x) means the y value that is created by using a specific x value as input.


Let s use f x 2 x 1 l.jpg

Let’s use f(x) = 2x + 1

The x inside the parentheses is the domain value.

The symbol f(x) is the range value.

The expression 2x + 1 tells us what we need to do to the domain value, in order to get our range value.

The entire symbol 2x + 1, represents a ______ value.


Evaluate each expression below l.jpg

Evaluate each expression below

Using f(x) = x³ , evaluate

  • f( 4)

    Using f(x) = -3x – 2, evaluate

  • f( -3)b) f( t )

    Using f(x) = x², evaluate

  • f(x – 3)b) f( x – h)

    Using f(x) = x² - 2x, evaluate

    a) f( x – h ) b) f( x ) c) f( x – h ) – f(x)


Does the equation represent y as a function of x l.jpg

Does the Equation represent y as a function of x ?

Let’s look at the equation x = y²

If this equation represents a function, then if we plug in a value for x, then it should produce only one value for y.

Let x = 4. This gives 4 = y² and so

y = 2 or y = -2

No, x = y² does not represent y as a function of x.


More examples l.jpg

More examples

Ex) x² + y² = 25

Ex)

Ex

Ex)


Evaluating the difference quotient l.jpg

Evaluating the Difference Quotient

The Difference Quotient for functions is defined to be

Evaluate the difference quotient for

  • f(x) = 3x + 1

    b) f(x) = x²

  • f(x) = x² - 2x

    d) f(x) = - 4x

  • Answers:

  • 3

  • 2x+h

  • 2x + h – 2

  • d) - 4


Finding domains for functions written as equations l.jpg

Finding Domains for functions written as Equations

If we have the function { ( 1, 5), ( 3, 7), (-2,0)}, then

Domain = { 1, 3, -2} and Range = { 5, 7, 0}

What would it mean if I asked you to find the domain for the function

To find the Domain for a function when it is written as an Equation, means to find all real x values that will produce real y values.


Let s look at l.jpg

Let’s look at

Let’s plug x values into the function and see what happens?

Consider the x values as Input and the y values as Output.

Ask yourself. What x values produce y values that are real?

These are the values we want to include in the domain.

Ask yourself. What x values produce y values that are not real?

These are the values we want to exclude from the domain.

Write the answer using interval notation.


How do you get nonreal y values l.jpg

How do you get Nonreal y values?

  • Dividing a number by zero, produces a nonreal y value.

    For example: 7/0 = not real or undefined

  • Taking the square root of a negative number.

    For example: is the same as ?² = - 4


Domains l.jpg

Domains

Find the domain for each function below. Write the answer using interval notation.

f(x) = 3x + 2


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Graphs of Nonfunctions

The relation is not a function.

{ ( 1,2), ( 3, -2), ( -1, 4), ( 1, -2)}

Let’s plot these points on the coordinate system. What do we notice?


Slide18 l.jpg

The two points (1,2) and ( 1, -2) have the same x value but different y value. They lie on the same vertical line.


Graphs of functions l.jpg

Graphs of Functions

The relation is a function

{ (-3, 2), ( -2, 1), ( -1, -3), ( 0, 2), ( 1, 3),

(2,0), ( 3, -2) }

Let’s plot these points on a coordinate system. What do we notice?


Slide20 l.jpg

This graph represents a function because you cannot find two points that lie on the same vertical line.


Determine which graphs represent functions l.jpg

Determine which graphs represent functions.

YES

NO

NO

YES


Find the domain and range l.jpg

Find the Domain and Range

Domain [ -5, 4 ]

Range [ 1, 7]


Find the domain and range23 l.jpg

Find the Domain and Range

Domain [ -4 , 3]

Range [ -3 , 0 ]


Find domain and range l.jpg

Find Domain and Range

Domain

Range


Find domain and range25 l.jpg

Find Domain and Range

Domain

Range


Slide26 l.jpg

f(x) is called an even function. The graph is symmetric with respect to the y –axis.

Notice:

f(2) = f( -2) = 3

f(4) = f( -4) = 1

Lastly, to be an even function means that

f (x) = f( - x )


Slide27 l.jpg

This function is an odd function. This means that the graph is symmetric with respect to the origin.

Notice:

f(2) = 3 and f( -2) = -3

f(5) = 2 and f( -5) = -2

In other words,

f( -2) = - f( 2) = - ( 3) = -3

f(- 5) = - f( 5) = -( 2) = -2

If a function is odd, this means

f(-x) = - f(x)


Slide28 l.jpg

An x- intercept is a point where a graph crosses the x- axis.

All x – intercepts are points with y = 0

( - 3, 0) and ( 2, 0)

A y – intercept is a point where the graph crosses the y – axis.

All y – intercepts are points with x = 0.

( 0, 4)


Intervals of increase or decrease l.jpg

Intervals of Increase or Decrease

increasing

decreasing

We say that f(x) is increasing on the interval ( -6, 0).

We say f(x) is decreasing on the interval ( 0, 4).

When determining intervals of increase or decrease, we read the graph from left to right. In other words, let the x values get larger.


Slide30 l.jpg

Over which intervals(months) was the account increasing?

Jan, Feb, March

Over which intervals(months) was the account decreasing?

April, May, July and August

Over which month(s) was the account constant?

June


Slide31 l.jpg

Find interval(s) where f(x) is increasing, decreasing or constant.

  • f(x) is increasing on

  • (-5, -1) or ( 4, 7)

b) f(x) is decreasing on

( -1, 4)

c) f(x) is never constant


Slide32 l.jpg

Determine the intervals where f(x) is increasing, decreasing or constant.

Increasing on ( - , -5) or ( 5, )

Constant on ( -5, 5)

f(x) is never decreasing


Slide33 l.jpg

The average rate of the change as x goes from o months to 5 months, says that if my money were to change by the same amount every month, it would change by $80 per month, in order to go from the original $100 to the final $500. It is the slope the secant line.


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Piece-wise Functions

Find a) f( 3)b) f(0)

c) f(-5)d) f( 4)


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Cell Phone Bill

Let’s say I have a program where I pay $50 if I talk between 0 and 100 minutes, inclusively.

If I talk pass 100 minutes, they charge 7 cents per minute, plus the $50 for the first 100 minutes.

Let x = number of minutes we talk on the phone for the month.


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