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Percent Yield

Percent Yield. Percent yield. % yield = actual yield Theoretical yield. X 100. If you started with 6.32 grams of N 2 , How many grams of ammonia should you produce? N 2 + 3H 2  2NH 3.

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Percent Yield

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  1. Percent Yield

  2. Percent yield % yield = actual yield Theoretical yield X 100

  3. If you started with 6.32 grams of N2 , How many grams of ammonia should you produce? N2 + 3H2 2NH3

  4. If you started with 6.32 grams of N2 , How many grams of ammonia should you produce? N2 + 3H2 2NH3 6.32g x 1 mol N2 x 2 mol NH3 x 17g NH3 = 28g 1 mol N2 1 mol NH3 = 7.67g NH3

  5. This was carried out in a lab. You obtained 7.41g of NH3 . What was your yield? % yield = 7.41 x100 97.7% 7.67

  6. What is the percent yield if 4.65 g Cu is produced when 1.87 g Al reacts with excess of CuSO4 ? 2Al (s) + 3CuSO4 (aq)  Al2(SO4) (aq) + 3Cu (s)

  7. What is the percent yield if 4.65 g Cu is produced when 1.87 g Al reacts with excess of CuSO4 ? 2Al (s) + 3CuSO4 (aq)  Al2(SO4) (aq) + 3Cu (s) 1.87gAl x 1 mol Al x 3 mol Cu x 63.5g Cu 27.0gAl 2 mol Al 1 mol Cu =6.60gCu ( theoretical ) %yield= 4.65g x100 6.60g = 70.5%

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