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# ANALYSIS OF A FOOTBALL PUNT - PowerPoint PPT Presentation

ANALYSIS OF A FOOTBALL PUNT. David Bannard TCM Conference NCSSM 2005. Opening thoughts. Watching St. Louis, Atlanta playoff game, the St. Louis punter punts a ball. At the top of the screen a hang-time of 5.1 sec. is recorded.

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### ANALYSIS OF A FOOTBALL PUNT

David Bannard

TCM Conference

NCSSM 2005

• Watching St. Louis, Atlanta playoff game, the St. Louis punter punts a ball.

• At the top of the screen a hang-time of 5.1 sec. is recorded.

• In addition, I observed that the ball traveled a distance of 62 yds.

• How hard did he kick the ball?

• Asked another way, how fast was the ball traveling when it left his foot?

• At what angle did he or should he have kicked the ball to achieve maximum distance?

• How much effect does the angle have on the distance?

• How much effect does the initial velocity have on the distance?

• Which has more, the angle or the initial V?

• What effect does wind have on the punt?

• Most algebra students have seen the equation

• Suppose we assume the initial height is 0.

When the ball lands, h = 0, so we have

• In other words, a hang-time of 5.0 sec. Would result from an initial velocity of 80 ft/sec

• Note that this solution only considers motion in one dimension, up and down.

• The graph of this equation is often misunderstood, as students often think of the graph as the path of the ball.

• To see the path the ball travels, the x-axis must represent horizontal distance and the y-axis vertical distance.

• Using vectors and parametric equations, we can analyze the problem differently.

• We will let X(t) be the horizontal component, I.e. the distance the ball travels down the field, and Y(t) be the vertical component, the height of the ball.

• Both components depend on the angle at which the ball is kicked and the initial V.

• The Ball leaves the foot with an initial velocity V0 at an angle q with the ground.

• The Ball leaves the foot with an initial velocity V0 at an angle q with the ground.

Initial Velocity V0

q

• The horizontal component depends only on V0t and the cosine of the angle.

Initial Velocity V0

q

• The horizontal component depends only on V0t and the cosine of the angle.

Initial Velocity V0

q

X(t)=V0t cos q

• The horizontal component depends only on V0t and the cosine of the angle.

• The vertical component combines v0t sinq and the effects of gravity, –16t2.

Initial Velocity V0

q

X(t) = V0t cos q

• The horizontal component depends only on V0t and the cosine of the angle.

• The vertical component combines v0t sinq and the effects of gravity, –16t2.

Initial Velocity V0

Y(t) = –16t2 + V0t sinq

q

X(t) = V0t cos q

• In parametric mode, enter the two equations.

• X(t)=V0t cos q + Wt where W is Wind

• Y(t)=–16t2+V0t sin q + H0 where H0 is the initial height.

• However we will assume W and H0 are 0

• Suppose that we start with t = 5 sec. and V0=80 ft./sec.

• We need an angle, and most students suggest 45° as a starting point.

• These values did not give the results that were predicted by the original h equation.

• Try using a value of q=90°.

• Assume that the kicking angle is 45°. Use trial and error to determine the initial velocity needed to kick a ball about 62 yards, or 186 feet.

• What is the hang-time?

• 1) How is the distance affected by changing the kicking angle?

• 2) How is the distance affected by changing the initial velocity?

• 3) Which has more effect on distance?

• Collect two sets of data from the class

• Set 1: Hold the velocity constant at 80 ft/sec. And vary the angle from 30° to 60°.

• Set 2: Hold the angle constant at 45° and vary the velocity from 60 ft/sec to 90 ft/sec.

• Accuracy will improve by making delta t smaller. Dt = 0.05 is fast. Dt = 0.01 is more accurate.

• Do we wish to interpolate?

• First estimate the hang-time with Dt = 0.1

• Use Calc Value to get close to the landing place.

• Choose t and X at the last positive Y.

### Use a Spreadsheet and/or calculator to collect data.

Then analyze the data using data analysis techniques on a calculator

• Can we determine how the distance the ball will travel relates to the initial velocity and the angle. In particular, why is 45° best?

• X(t) = V0t cos q and Y(t) = –16t2 + V0t sin q

• When the ball lands, Y = 0, so

• –16t2 + V0t sin q = 0 or t (–16t + V0 sinq) = 0

• So t = 0 or V0 sinq/16.

• But X(t) = V0t cos q

• X(t) = V0t cos q and Y(t) = –16t2 + V0t sin q

• When the ball lands, Y = 0, so

• –16t2 + V0t sin q = 0 or t (–16t + V0 sinq) = 0

• So t = 0 or V0 sinq/16.

• But X(t) = V0t cos q

• Substituting gives

• X(t) = V0t cos q and Y(t) = –16t2 + V0t sin q

• When the ball lands, Y = 0, so

• –16t2 + V0t sin q = 0 or t (–16t + V0 sinq) = 0

• So t = 0 or V0 sinq/16.

• But X(t) = V0t cos q

• Substituting gives

• Using the double angle identity gives

• How do hang-time and height vary with q and V0?

• We already know the t = V0 sinq/16

• The maximum height occurs at t/2, so

• How do hang-time and height vary with q and V0?

• We already know the t = V0 sinq/16

• The maximum height occurs at t/2, so

Final QuestionIf we know the hang-time, and distance, can we determine V0 and q?

• Given that when Y(t)=0, we know X(t) and t.

• Therefore we have two equations in V0 and q, namely

• X = V0t cos q and 0 = –16t2 + V0t sinq.

• Solve both equations for V0 and set them equal.

• Given that when Y(t)=0, we know X(t) the distance and t, the hang-time.

• Therefore we have two equations in V0 and q, namely

• X = V0t cos q and 0 = –16t2 + V0t sinq.

• Solve both equations for V0 and set them equal.