- 93 Views
- Uploaded on
- Presentation posted in: General

Forces and Inclines

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Forces and Inclines

- Objects placed on a tilted surface tend to slide down the surface
- The rate at which it slides will be dictated by the angle of the incline…greater tilt = greater rate of slide
- An object that accelerates down an incline must do so because of unbalanced forcein that direction

- There are always at least two forces acting on an object on an incline…

- Normal force will ALWAYS be perpendicular to the inclined surface…

- ALWAYS straight down
- ALWAYS at an angle with respect to the inclined surface

- The weight can be resolved into two components.
- One component is
aligned parallel to the

inclined surface

- One component is
aligned perpendicular

to the inclined surface

- One component is

- For purposes of problem solving, redefine the x-axis to line up with the inclined surface and the y-axis to be perpendicular to the inclined surface.
- This makes the parallel
component of the weight

in “x” direction

- This makes the perpendicular
component of the weight and

the normal force in the “y”

direction

- This makes the parallel

y

x

FN

Fgx

Fgy

Fg

- The angle between the weight vector and the new y-axis is the same angle as the incline.

x

y

θ

θ

Fg

- The perpendicular component is along the y-axis and its magnitude is given by:

x

y

Fgcosθ

θ

θ

Fg

- The parallel component is along the x-axis and its magnitude is given by:

x

y

Fgsinθ

θ

θ

Fg

The force in the direction down the incline gets larger while the component into the surface gets smaller

- A 25 kg crate is sitting at rest on a ramp inclined at 25 degrees. Find the normal force and the frictional force acting on the crate. Then find µs between the crate and the ramp.

- A 4.5 kg object is accelerating down an inclined plane inclined at 36 degrees and having a coefficient of friction of 0.548. What is the acceleration of the object?

- A 22.7-N block is placed upon an inclined plane which is inclined at a 17.2 degree angle. The coefficient of friction is 0.219. Determine the acceleration of the block if the applied force of 20.6 N is acting up the ramp.

- The infamous Lombard Street in San Francisco has an abnormally steep block which consists of several tight hairpin turns. On average, the roadway on this block of the street is inclined at 16°. Determine the force which would be required to pull a 23-kg wagon and child up the hill at constant speed. Assume the force is exerted parallel to the road and that friction is negligible.

- Ben Laborin exerts a force on an 86-kg crate of books to push it up the ramp of the loading dock at a constant speed of 24 cm/s. The ramp makes an angle of 12° with the horizontal. The coefficient of friction between the crate and the ramp is 0.74. Assuming that Ben is pushing parallel to the inclined plane, determine the force with which he is pushing.