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Year 11 Physics Term 3 Week 9

Year 11 Physics Term 3 Week 9. Working With Complex Circuits. The first objective when working with complex circuits is to find the equivalent resistance of the entire circuit. Remember that R eq in a series circuit is the sum of all individual resistances. R eq in parallel circuits:

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Year 11 Physics Term 3 Week 9

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  1. Year 11 Physics Term 3 Week 9 Working With Complex Circuits

  2. The first objective when working with complex circuits is to find the equivalent resistance of the entire circuit. Remember that Req in a series circuit is the sum of all individual resistances Req in parallel circuits: 1 = 1 + 1 + 1 . . . Req R1 R2 R3

  3. 2 ohms 3 ohms Total Resistance is 12 ohms 1. Find the equivalent resistance of all parallel parts. 2. Add these equivalent resistances to the series resistances. This will give you the total resistance of the entire circuit.

  4. The second objective is to find the total current in the circuit. To find the total current divide the Source voltage by the total Resistance Itotal = Vsource Rtotal

  5. The third objective is to assign this total current to each of the components of the complex circuit that are in series with each other since current is not divided in a series circuit. Current is the same everywhere in a series circuit!

  6. Total Current = 2 amps 2A 2A 2A 2A

  7. Now you know both the current and the resistance of each part of the complex circuit so next you can determine how the voltage will be split.

  8. 2A 8V 2A 4V Req=2  6V 2A Req=3  2A 6V The two series parts are complete now. You know V, I, and R. Let’s finish the two parallel parts. Notice how all the voltages add up to the source voltage of 24V!! Voltage = IR. Calculate the voltage for each part.

  9. The 2A coming in here will be split evenly since the 2 resistors are the same. 1A 1A To figure out how the 2A will be split among these 3 branches, use the voltages we figured out before and the resistance of each branch. I=V/R I=6/12=.5A I=6/12=.5A I=6/6=1A Remember that in parallel circuits, all branches get the same voltage. Notice how the branch currents add up to the 2A we had coming into the parallel part? That means each parallel branch is going to receive 6V

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