Solving multi step equations
This presentation is the property of its rightful owner.
Sponsored Links
1 / 12

Solving Multi-Step Equations PowerPoint PPT Presentation


  • 173 Views
  • Uploaded on
  • Presentation posted in: General

Solving Multi-Step Equations. 7.2. Useful Steps to Solve a Multi-Step Equations. Distribute (if necessary) Combine like terms (if one same side of equation) Undo addition or subtraction Undo multiplication or division. 2x + 7 + x =16. 3x+7 =16 3x =9 X=3. -3(m-6)=4. -3m +18 =4 -3m=-14

Download Presentation

Solving Multi-Step Equations

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


Solving multi step equations

Solving Multi-Step Equations

7.2


Useful steps to solve a multi step equations

Useful Steps to Solve a Multi-Step Equations

  • Distribute (if necessary)

  • Combine like terms (if one same side of equation)

  • Undo addition or subtraction

  • Undo multiplication or division


2x 7 x 16

2x + 7 + x =16

3x+7 =16

3x =9

X=3


3 m 6 4

-3(m-6)=4

-3m +18 =4

-3m=-14

M =14/3


3 x 12 x 8

3(x+12)-x=8

3x+36 –x =8

2x +36 =8

2x=-28

X=-14


2 x 1 x 7

2(x+1) +x=7

2x+2 +x =7

3x +2 =7

3x =5

X= 5/3


Consecutive numbers

Consecutive Numbers

  • Counting by ones from any integer

  • Examples:

    120,121,122,…

    -5,-4,-3,…

  • Formula:

    n, n+1, n+2, n+3, n+4….


Consecutive even integers

Consecutive Even Integers

  • Counting by evens from any integer

  • Examples:

    2,4,6,8,…

    122,124,126,128…

  • Formula:

    n, n+2, n+4, n+6, n+8, n+10


Consecutive odd integers

Consecutive Odd Integers

  • Counting by odds from any integer

  • Examples:

    …,-9,-7,-5,-3

    83,85,87,89,…

  • Formula:

    n, n+2, n+4, n+6, n+8, n+10


Find four consecutive integers with a sum of 358

Find four consecutive integers with a sum of 358

n + (n+1)+ (n+2)+ (n+3) = 358

4n+6 =358

4n =352

n =88

n+1=89

n+2=90

n+3=91

Answer: 88,89,90,91


Find two consecutive even integers with a sum of 66

Find two consecutive even integers with a sum of 66.

n + (n+2) =66

2n+2 =66

2n=64

n=32

n+2=34

Answer:32, 34


Homework

Homework

  • Page 343 (11-29) all


  • Login