- 112 Views
- Uploaded on
- Presentation posted in: General

Forces: Maintaining Equilibrium or Changing Motion

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Forces:Maintaining Equilibrium or Changing Motion

PSE4U

Mr. MacMillan

- A gymnast maintains a position on one foot during a balance beam routine. A rock climber clings by her fingertips to the face of a cliff.
- What are the forces that act on each of these athletes?
- How do athletes manipulate these forces in order to maintain balance?

- A force is a push or pull
- They are exerted by objects on other objects
- A force is something that accelerates or deforms an object.
- A force is measured is a Newton
- This is named after Sir Isaac Newton
- 1 N of force is defined as the force required to accelerate 1 kg mass 1 m/s/s
- 1.0 N = (1.0 kg)(1.0 m/s/s)

- Internal Forces
- Are forces that act within the object or system whose motion is being investigated
- Internal pulling forces – tensile forces
- Internal pushing forces – compressive forces

- Examples of internal forces
- Muscles

- Are forces that act within the object or system whose motion is being investigated

- External Forces
- Forces that act on an object as a result of it’s interaction with the environment surrounding it

- Examples of external forces
- The force of gravity
- Magnetic forces
- Electrical forces

- Weight
- The force of gravity acting on an object
- W = mass x acceleration due to gravity = m x g (9.81 m/s/s)

- To estimate the weight of something you multiply its mass by 9.81.

- Forces that occur between objects in contact with each other
- Examples: Air resistance, water, reaction forces

- Static Friction
- Dry friction between two surfaces that are not moving relative to each other
- Also referred to as limiting friction

- Dynamic friction
- Dry friction between two surfaces that are moving relative to each other
- Also known as sliding friction and kinetic friction

- Lets do some experimentation to learn more about friction. Place a book on a flat horizontal surface such as a desk or tabletop. Now push sideways against the book and feel how much force you can exert before the book begins to move.
- What force resists the force that you exert on the book and prevents the book from sliding?
- Static friction
- If the book doesn’t slide then the static friction force acting on the book is the same size as the force you exerted on the book.

- Now add another book on top of the original and push again.
- Can you push with a greater force before the book begins to move?
- Add another book. What happens?

- As you add books to the pile, the magnitude of the force you exert before the books slide becomes bigger and so does the static friction force

- Mathematically we can express static and dynamic friction as:
- Static: Fs= usR
- us = coefficient of static friction
- R = normal contact force

- Dynamic: Fd = ud R
- ud = coefficient of dynamic friction
- R = normal contact force

- Forces are added using the process of vector addition
- The result of vector addition of two or more forces is called a resultant force
- The vector addition of all the external forces acting on an object is the net force.
- Colinear Forces are forces that have the same line of action.

- A spotter assists a weightlifter who is attempting to lift a 1000 N barbell. The spotter exerts an 80 N upward force on the barbell, while the weight lifter exerts a 980 N upward force on the barbell. What is the net force exerted on the barbell?

- Total Force = 80 N + 980 N + (-1000 N) = 60 N
- The net vertical force acting on the barbell is a 60 N force acting upward

- Do not act along the same line, but they do act through the same point
- i.e. a gymnast on the high bar

- A gymnast jumps up and grasps the high bar and his coach stops his swinging by exerting forces on the front and back of the gymnast’s torso. The external forces acting on the gymnast are the force of gravity acting on the mass of the gymnast, a horizontal force of 20 N exerted by the coach pushing on the front of the gymnast, a horizontal force of 30 N exerted by the coach on the back of the gymnast, and an upward vertical reaction force of 550 N exerted by the bar on the gymnast’s hands. The gymnast’s mass is 50 kg.
- What is the net external force acting on the gymnast?

30 N

20 N

W = 500 N

- First, how large is the force of gravity acting on the gymnast?
- W = mg
- = (50 kg)(10 m/s/s) = 500 kg m/s/s = 500 N

30 N

- Using an appropriate scale, draw all forces

550 N

500 N

Resultant force 51 N

20 N

Resultant Force 51 N

50 N

10 N

- A2= B2 + C2
- Pythagorean theorem

- Sample Problem
- The vertical ground reaction force (normal contact force) acting under a runners force is 2000 N, while the frictional force is 600 N acting forward. What is the resultant of these two forces?

- Draw the forces
- Draw the resultant force
- Compute the resultant force

- Research a career in the field of biomechanics
- Give a one paragraph description of the career you chose
- Find out what qualifications you need for the job and describe the program(s) you may need to take in college/university and/or special training
- List 3 schools where you can get these qualifications
- Find the average salary and, if there is one, a pay scale for the profession
- What is the job prospects in the future? Are there any available jobs? Find an advertisement online to support your claims.