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Section 6 Digital Combinational CircuitsPowerPoint Presentation

Section 6 Digital Combinational Circuits

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Section 6 Digital Combinational Circuits

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Section 6

Digital Combinational Circuits

- Combinational
- Static
- Dynamic

- Sequential
- Static
- Dynamic

VDD

- CMOS Circuits
- Pull-up network-PMOS
- Pull-down network- NMOS
- Networks are complementary to each other
- When the circuit is dormant, no current flows between supply lines.
- Number of the NMOS transistors (PMOS transistors) equals to the number of the inputs.
- Output load is capacitive

PMOS

Network

Output

Inputs

NMOS

Network

Transistors in Parallel

1/Rcheff = (1/Rch1) + (1/Rch2)

Transistors in Series

Rcheff = Rch1 + Rch2

DC Analysis

Two possible scenarios:

1. Both inputs are toggling

2. One input is toggling, the other one set high

Assumptions: MP2=MP1=MP

MN1=MN2=MN

W/L for MP = (W/L)p

W/L for MN = (W/L)n

Compare with a CMOS inverter: MP/MN

Determine KR, hence the shift in VTC

Scenario #1-

Both inputs are toggling

L-H > (W/L)eff = 2(W/L)p

H-L > (W/L)eff = 1/2(W/L)n

KR|NAND = 1/4 KR|INV

Scenario #2-

One input is toggling

L-H > (W/L)eff = (W/L)p

H-L > (W/L)eff = 1/2(W/L)n

KR|NAND = 1/2 KR|INV

Vin

Inverter

One input toggling

V

OH

Two inputs toggling

Vin=Vout

V

OL

Vout

Vx2 Vx1

Switching Analysis

Scenario #1-

Both inputs are toggling

tPLH |NAND = 1/2tPLH |INVERTER

tPHL |NAND = 2tPHL |INVERTER

Scenario #2-

One input is toggling

tPLH |NAND = tPLH |INVERTER

tPHL |NAND = 2tPHL |INVERTER

Layout

Transistors in Series

Transistors in Parallel

VDD

Via

Metal II

X

A

B

GND

Pac= .f . C VDD2

A B X

0 0 1

1 0 1

0 1 1

1 1 0

= P (X=1). P (X=0)

assuming A and B have equal probabilities for 1 and 0

= (1/4). (3/4)= 3/16

C = CL + C parasitic

1. Draw the schematic

2. Do the stick diagram

3. Optimize stick diagram

4. Generate Layout

DC Analysis/ AC Analysis

Two possible scenarios:

1. Both inputs are toggling (one is set low)

2. One input is toggling, the other one set high

Assumptions: MP2=MP1=MP

MN1=MN2=MN

W/L for MP = (W/L)p

W/L for MN = (W/L)n

Compare with a CMOS inverter: MP/MN

KR, and the shift in VTC

Propagation delay tPLH andtPHL

VDD

X

B

A

GND

VDD

Very slow rise time and rise delays

Could be compensated by increasing

of PMOS transistor size.

Implications:

Silicon Area

Input capacitance

A

B

C

D

X

B

C

A

C

D

L

1. Minimize the use of NOR gates

2. Minimize the fan-in of NOR gates

3. Limit the fan-in to 4 for NAND gates

4. Use De morgan’s theorem to reduce the number of fan-in per gate

Example:

p+ layer

contact

n+ layer

active

polysilicon

metal

(diffusion)

Analysis

1. Construct the schematic

2. Determine the logic function.

3. Determine transistor sizes.

4. Determine the input pattern to

cause slowest and fastest

operations.

5. Determine the worst case rise

delay (tPLH)and fall delay (tPHL)

6. Determine the best case rise

and fall delays.

A B C D E F

VDD

OUT

N-well

GND

A B C D E F

Bi-directional switch, passes digital signals

Less complex and more versatile than AND gate

Passes analog signals

Problems:

Large ON resistance during transitions of input signals

Large input and output capacitance

(useful for data storage applications)

Capacitive coupling

Applications:

Multiplexers, encoders, latches, registers

various combinational logic circuits

C

A

B

C

NMOS Transistor

Passes weak “1” signal

Vo = VDD -VTN

Passes “0” signal undegraded

C

Vo

VDD -VTN

Vi

Vo

CL

VDD -VTN

Vi

PMOS Transistor

Passes “1” signal undegraded

Passes weak “0” signal

Vo= -VTP

Vo

C

Vi

Vo

-VTP

CL

Vi

-VTP

Vo

Vin

nmos:sat nmos:sat nmos:off

pmos:sat pmos:lin pmos:lin

0V |VTP| VDD-VTN VDD

0

C

VDD

P+

P+

Vi

VO

N+

N+

C

VSS

C

C

For data path structure

Exclusive OR

12 Transistors

8 Transistors

Multiplexers

Realization of Combinational Logic Functions