1 / 7

Example on Critical Path and Float Time Calculations:

Example on Critical Path and Float Time Calculations:. Problem: Calculate the float for all activities in network. According to the network diagram P1{1,4} needs 20 days P2{1,5} needs 26 days P3{2,3,5} needs 34 days P4{2,3,4} needs 28 day Therefore P3 is the critical path Pcp=34.

juliecoleman
Download Presentation

Example on Critical Path and Float Time Calculations:

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Example on Critical Path and Float Time Calculations:

  2. Problem: Calculate the float for all activities in network.

  3. According to the network diagram • P1{1,4} needs 20 days • P2{1,5} needs 26 days • P3{2,3,5} needs 34 days • P4{2,3,4} needs 28 day • Therefore P3 is the critical path Pcp=34. Solution.

  4. Activities 2, 3, and 5 are on the critical path; they have zero float • But activities 1 and 4 are not on the critical path… Hence,

  5. The float for activities 1 is Pcp-P2 = 34-26= 8 days Since activity 1 is on P2(1,5}

  6. But P4 takes longer, so • The float for activity 4 is Pcp-P4 = 34-28 = 6 days And activity 4 is on P1 and P4

  7. Activity 1 can have a slippage of 8 days • Activity 4 can have a slippage of 6 days. Conclusion…

More Related