Angle of elevation angle of depression
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Angle of Elevation & Angle of Depression PowerPoint PPT Presentation


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Angle of Elevation & Angle of Depression. When a person looks at something above his/her location, the angle between the line of sight and the horizontal is called the angle of elevation . In this case, the line of sight is "elevated" above the horizontal. Object. Eye.

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Angle of Elevation & Angle of Depression

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Angle of elevation angle of depression

Angle of Elevation& Angle of Depression


Angle of elevation angle of depression

When a person looks at something above his/her location, the angle between the line of sight and the horizontal is called the angle of elevation. In this case, the line of sight is "elevated" above the horizontal.

Object

Eye


Angle of elevation angle of depression

When a person looks at something below his or her location, the angle between the line of sight and the horizontal is called the angle of depression. In this case, the line of sight is "depressed" below the horizontal.

Eye

Object


Angle of elevation angle of depression

A stands at the window of a

so that his are 12.6 m above the

level ground in the vicinity of the

An object is 58.5 m away from the

on a line directly beneath the

Find the angle of depression of the

person's line of sight to the object on the

ground.


Solutions

Solutions

  • = angle of depression

  12.15º

eye

Line of sight

12.6m

Ground level

object

58.5m


Exercise

Exercise

Calculate the angle of elevation of the

line of sight of a person whose eye is

1.7m above the ground, and is looking

at the top of a tree which is 27.5 m away

on level ground and 18.6 m high.


Sketch

Sketch


Solution

Solution

  31.57º

Angle of elevation of this person line of sight is 31.57º


Angle of depression

Angle of depression

Find the height of the man in the

hot air balloon from the ground.

= 50°

h =100 tan 50°

= 119.2m

h

100m


Find the height of the tower

Exercise

FIND THE HEIGHT OF THE TOWER

Height of tower

= 53 tan 80°

= 300.6m

80º

53m


Exercise1

Exercise

From the top of a vertical cliff 40 m high,

the angle of depression of an object

that is level with the base of the cliff is

34º. 

How far is the object from the base of

the cliff?


Solution1

Solution

Let x m be the distance of the object

from the base of the cliff.


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