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Equations for Projectile Motion

Equations for Projectile Motion. Horizontal Vertical a x = 0 a y = - g v x = constant. Steps in Solving Problems. Draw free-body diagram for every object that is ”free”

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Equations for Projectile Motion

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  1. Equations for Projectile Motion Horizontal Vertical ax=0 ay = - g vx= constant

  2. Steps in Solving Problems • Draw free-body diagram for every object that is ”free” • Select coordinate system such that one of the axis is along the direction of acceleration • Write out the equations of motion for the x and y coordinate: • Step 2 should guarantee that the sum of the forces in at all but one direction equals zero. • Solve the equations simultaneously

  3. Non-Conservative Forces • If work is done by non-conservative forces: • The sign of WNC is very important • A motor adds energy so WNC is positive and E2 > E1 • Friction dissipates energy so WNC is negative and E2 < E1

  4. Example 6-5(43) The roller-coaster car shown is dragged up to point 1 where it is released from rest. Assuming no friction, calculate the speed at points 2, 3, and 4. Let point be the height where P.E. = 0 Ch 6 5

  5. Continued Example 6-5(43) The roller-coaster car shown is dragged up to point 1 where it is released from rest. Assuming no friction, calculate the speed at points 2, 3, and 4. Let point be the height where P.E. = 0 Ch 6 6

  6. F12 F21 Conservation of Momentum In the collision of two isolated objects, the only forces are between the two objects—these are called internal forces. In this case: initial momentum = final momentum The total momentum of an isolated system of bodies remains constant.

  7. Radial and Tangential Acceleration A point on a rotating wheel always has centripetal acceleration and it will have tangential acceleration if the wheel has angular acceleration.

  8. Kinematic Equations for Uniformly Accelerated Motion The angular equations for constant angular acceleration are derived the same as for constant linear acceleration.

  9. Rotational Dynamics Torque is necessary for angular acceleration This is expressed as where I is called the moment of inertia Compare this with Newton’s Second Law: • τ is the equivalent of force for rotational motion • I is the equivalent of mass for rotational motion

  10. A 1.5 kg mass is attached to a cord wrapped around a heavy pulley of mass 4.00 kg and radius 33.0 cm. The pulley is a solid cylinder. Calculate the acceleration of the mass. m Example 8-5

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