1 / 12

Overpotential

Overpotential. When the cell is producing current, the electrode potential changes from its zero-current value, E, to a new value, E’. The difference between E and E’ is the electrode’s overpotential , η . η = E’ – E The ∆ Φ = η + E, Expressing current density in terms of η

jorn
Download Presentation

Overpotential

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Overpotential • When the cell is producing current, the electrode potential changes from its zero-current value, E, to a new value, E’. • The difference between E and E’ is the electrode’s overpotential, η. η = E’ – E • The ∆Φ = η + E, • Expressing current density in terms of η ja = j0e(1-a)fη and jc = j0e-afη where jo is called the exchange current density, when ja = jc

  2. The low overpotential limit • The overpotential ηis very small, i.e. fη <<1 • When x is small, ex = 1 + x + … • Therefore ja = j0[1 + (1-a) fη] jc = j0[1 + (-a fη)] • Then j = ja - jc = j0[1 + (1-a) fη] - j0[1 + (-a fη)] = j0fη • The above equation illustrates that at low overpotential limit, the current density is proportional to the overpotential. • It is important to know how the overpotential determines the property of the current.

  3. Calculations under low overpotential conditions • Example: The exchange current density of a Pt(s)|H2(g)|H+(aq) electrode at 298K is 0.79 mAcm-2. Calculate the current density when the over potential is +5.0mV. Solution: j0 =0.79 mAcm-2 η = 6.0mV f = F/RT = j = j0fη

  4. The high overpotential limit • The overpotential ηis large, but could be positive or negative!!! • When η is large and positive j0e-afη= j0/eafη becomes very small in comparison to ja Therefore j ≈ ja = j0e(1-a)fη ln(j) = ln(j0e(1-a)fη ) = ln(j0) + (1-a)fη • When η is large but negative ja is much smaller than jc then j ≈ jc = j0e-afη ln(j) = ln(j0e-afη ) = ln(j0) – afη • Tafel plot: the plot of logarithm of the current density against the over potential.

  5. Calculations under high overpotential conditions • The following data are the anodic current through a platinum electrode of area 2.0 cm2 in contact with an Fe3+, Fe2+ aqueous solution at 298K. Calculate the exchange current density and the transfer coefficient for the process. η/mV 50 100 150 200 250 I/mA 8.8 25 58 131 298 Solution: calculate j0 and a Note that I needs to be converted to J

  6. The general arrangement for electrochemical rate measurement

  7. Voltammetry • Voltammetry: the current is monitored as the potential of the lectrode is changed. • Chronopotentiometry: the potential is monitored as the current density is changed. • Voltammetry may also be used to identify species and determine their concentration in solution. • Non-polarizable electrode: their potential only slightly changes when a current passes through them. Such as calomel and H2/Pt electrodes • Polarizable electrodes: those with strongly current-dependent potentials.

  8. Concentration polarization • Concentration polarization: The consumption of electroactive species close to the electrode results in a concentration gradient and diffusion of the species towards the electrode from the bulk may become rate-determining. Therefore, a large overpotential is needed to produce a given current. • Eqns 29.42 to 29.53 will be discussed in class • Example 29.3: Estimate the limiting current density at 298K for an electrode in a 0.10M Cu2+(aq) unstirred solution in which the thickness of the diffusion layer is about 0.3mm.

  9. Experimental techniques in voltammetry

  10. Experimental techniques in voltammetry

  11. Experimental techniques in voltammetry

  12. Electrolysis • Cell potential: the sum of the overpotentials at the two electrodes and the ohmic drop due to the current through the electrolyte (IRs). • Electrolysis: To induce current to flow through an electrochemical cell and force a non-spontaneous cell reaction to occur. • Estimating the relative rates of electrolysis.

More Related