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# 5.2 Definite Integrals - PowerPoint PPT Presentation

5.2 Definite Integrals. Greg Kelly, Hanford High School, Richland, Washington. When we find the area under a curve by adding rectangles, the answer is called a Rieman sum. The width of a rectangle is called a subinterval. The entire interval is called the partition. subinterval.

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Presentation Transcript

Greg Kelly, Hanford High School, Richland, Washington

When we find the area under a curve by adding rectangles, the answer is called a Rieman sum.

The width of a rectangle is called a subinterval.

The entire interval is called the partition.

subinterval

partition

Subintervals do not all have to be the same size.

If the partition is denoted by the answer is called a P, then the length of the longest subinterval is called the norm of P and is denoted by .

As gets smaller, the approximation for the area gets better.

subinterval

partition

if P is a partition

of the interval

is called the the answer is called a definite integral of

over .

If we use subintervals of equal length, then the length of a subinterval is:

The definite integral is then given by:

Note that the very small change in x becomes dx.

It is called a dummy variable because the answer does not depend on the variable chosen.

upper limit of integration

Integration

Symbol

integrand

variable of integration

(dummy variable)

lower limit of integration

velocity learn how to evaluate the integral.

time

In section 5.1, we considered an object moving at a constant rate of 3 ft/sec.

Since rate . time = distance:

If we draw a graph of the velocity, the distance that the object travels is equal to the area under the line.

After 4 seconds, the object has gone 12 feet.

If the velocity varies: learn how to evaluate the integral.

Distance:

(C=0 since s=0 at t=0)

After 4 seconds:

The distance is still equal to the area under the curve!

Notice that the area is a trapezoid.

What if: learn how to evaluate the integral.

We could split the area under the curve into a lot of thin trapezoids, and each trapezoid would behave like the large one in the previous example.

It seems reasonable that the distance will equal the area under the curve.

The area under the curve learn how to evaluate the integral.

We can use anti-derivatives to find the area under a curve!

Let area under the curve from learn how to evaluate the integral.a to x.

(“a” is a constant)

Let’s look at it another way:

Then:

min learn how to evaluate the integral.f

max f

h

The area of a rectangle drawn under the curve would be less than the actual area under the curve.

The area of a rectangle drawn above the curve would be more than the actual area under the curve.

As learn how to evaluate the integral.h gets smaller, min f and max f get closer together.

This is the definition of derivative!

initial value

Take the anti-derivative of both sides to find an explicit formula for area.

As learn how to evaluate the integral.h gets smaller, min f and max f get closer together.

Area under curve from a to x = antiderivative at x minus antiderivative at a.

Area learn how to evaluate the integral.

Example: learn how to evaluate the integral.

Find the area under the curve from x=1 to x=2.

Area under the curve from x=1 to x=2.

Area from x=0

to x=2

Area from x=0

to x=1

ENTER learn how to evaluate the integral.

2nd

7

Example:

Find the area under the curve from x=1 to x=2.

To do the same problem on the TI-89:

Example: learn how to evaluate the integral.

Find the area between the

x-axis and the curve

from to .

pos.

neg.

On the TI-89:

If you use the absolute value function, you don’t need to find the roots.

p