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Quadratic BINGO

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Directions:

1. This will be turned in so show your work neatly! NO TALKING ALLOWED!!!

2. Work each problem on your own paper.

3. Circle your answer.

(Bingo directions to follow after the problems.)

1. Convert to standard form:y = (x+3)² - 2

8. What is the

minimum value of

the function? Where

does the min occur?

9. Describe the end behavior of the graph:

As x→-∞ , f(x) → ___

and

As x→+∞ , f(x) → ___

10. Convert to standard form:

y = -2 (x-2)² - 4

11. Solve (by any method):

2x² - 15x = -7

12. What is the domain of the graph of

y = -3x² +5x -6 ?

13. Is (4,-3) a solution for the equation

y ≤ ½ x² + 5x + 3 ?

14. Solve (by any method):

5x² - 5x = -5

15. Find x. Area = 44

X + 4

X - 3

16. What is the interval of increase for the graph?

17. Solve algebraically.

2x² - 5x -4 ≥ 0

(write answer as an inequality)

18. What is the axis of symmetry for the graph of the equation

Y = -2(x+5)² -5?

19. Describe the value of the discriminantof the function whose graph is shown here. (hint: positive, negative, or zero)

20. What is the interval of decrease of the graph shown?

- 21. Which of the following inequalities is graphed here?
- y ≥ -x² + 4x -3
- y > -x² + 4x -3
- y < -x² + 4x -3
- y ≤ -x² + 4x -3

22. Solve the equation:

2x² + 8 = 0

23. Factor.

5x² - 2x - 3

24. Write in vertex form:

y = x² + 6x - 5

Now take each of the answers you got and write them in one of the boxes on you BINGO card. Use each answer only once! Your card must be completely filled in order to play the game. If you didn’t finish a question, then put an “X” in a box. That box won’t be used to play the game. Put your name on your paper and turn it in now!

An answer will appear on the screen. If you have that answer on your sheet put a check mark on it. Once you get 5 answers in a row marked, call out “BINGO”. Once your answers are verified you will receive a prize. ALL ANSWERS MUST BE WRITTEN THE WAY THEY APPEAR ON THE SCREEN TO BE CORRECT. (ex. X=3 not just 3)

(1,7)

Y = (x + 3)² - 14

(-∞, 6]

X = 0 , -4

( -∞, +∞)

X = 7

( 5x + 3)( x – 1 )

( -∞, 1)

X = ± 2i

( -4,+∞)

Y = -2x² + 8x - 12

+∞

+∞

X = -5

Min Value = -3 @ x =-4

x² + 6x +7

Y = (x + 1)² - 5

Negative

B

X < -½ or x > 3

Yes, it is a solution

X = ½, 7