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# Lecture 5 - PowerPoint PPT Presentation

Lecture 5. Source Transformation Thevenin Equivalent Circuit Norton Equivalent Circuit. Source Transformation. Show that i S = v S /R for any R L. Application. Determine whether the 6V source is absorbing or delivering the power. Step-by-step simplification. Redundant Resistor (1).

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## PowerPoint Slideshow about ' Lecture 5' - jenski

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Presentation Transcript

### Lecture 5

Source Transformation

Thevenin Equivalent Circuit

Norton Equivalent Circuit

Show that iS=vS/R for any RL

Determine whether the 6V source is

absorbing or delivering the power.

Prove that the left circuit and the right circuit are

Prove that the left circuit and the right circuit are equivalent for any load resistor.

Thevenin Equivalent Circuit

VTh

• If RL=∞, then Vab=VTH

• If RL=0, the short circuit current from a to b (i.e. iab) should equal to isc=VTh/RTH.

• So RTH=VTh/isc

Determine vab

Show that VTH=vab

Determine iSCand RTH

Determine the Thevenin Equivalent Voltage

Determine the short circuit current

Determine RTH

• RTH=VTH/iSC

• If the network contains only independent soruces:

• Deactivate a voltage source by replacing it with a short

• Deactivate a current source by replacing it with an open

• If the network contains dependent sources

• Apply a test source

RTH

RTH

• A Norton Equivalent circuit consists of

• Short-Circuit Current

• Norton Equivalent Resistance, which is equal to Thevenin Equivalent Resistance

Derive 4.1-4.3