- 56 Views
- Uploaded on
- Presentation posted in: General

Solution Stoichiometry (Lecture 3)

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Solution Stoichiometry(Lecture 3)

More examples on volumetric analysis calculations

- More examples on Volumetric analysis calculations

- Example 3Calculate the volume of nitric acid of concentration 0.200 moldm-3 required to react completely with 4.0 g of copper(II) oxide.

Balanced equation

Given mass

v??

Given c

- Example 3Calculate the volume of nitric acid of concentration 0.200 moldm-3 required to react completely with 4.0 g of copper(II) oxide.

Balanced equation

- Example 3Calculate the volume of nitric acid of concentration 0.200 moldm-3 required to react completely with 4.0 g of copper(II) oxide.

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

- Example 4In an experiment, 25.0 cm3 of sodium hydroxide of concentration 4.00 gdm-3 completely reacted with 18.0 cm3 of sulphuric acid. Calculate the molar concentration of the sulphuric acid.

Balanced equation

Given c (in gdm-3), and V

c??

Given V

- Example 4In an experiment, 25.0 cm3 of sodium hydroxide of concentration 4.00 gdm-3 completely reacted with 18.0 cm3 of sulphuric acid. Calculate the molar concentration of the sulphuric acid.

Balanced equation

- Example 4In an experiment, 25.0 cm3 of sodium hydroxide of concentration 4.00 gdm-3 completely reacted with 18.0 cm3 of sulphuric acid. Calculate the molar concentration of the sulphuric acid.

Balanced equation

Balanced equation

Balanced equation

Balanced equation

- Example 510.0 g of anhydrous sodium carbonate was dissolved in water, and made up to 250 cm3 of solution. 25.0 cm3 of this solution required 20.0 cm3 of HCl solution for neutralisation. Calculate the concentration of the HCl solution.

Balanced equation

c??

Given mass in certain V

Given V

Can calculate c

Given V

- Example 510.0 g of anhydrous sodium carbonate was dissolved in water, and made up to 250 cm3 of solution. 25.0 cm3 of this solution required 20.0 cm3 of HCl solution for neutralisation. Calculate the concentration of the HCl solution.

Balanced equation

- Example 510.0 g of anhydrous sodium carbonate was dissolved in water, and made up to 250 cm3 of solution. 25.0 cm3 of this solution required 20.0 cm3 of HCl solution for neutralisation. Calculate the concentration of the HCl solution.

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

Balanced equation

- More examples on Volumetric analysis calculations

End of Lecture 3

“Often greater risk is involved in postponement than in making a wrong decision” Harry A Hopf