Start-Up. What is the molar mass for Calcium hydroxide? A. 57.08 g/mol B. 74.08 g/mol C. 64.08 g/mol D. 27 g/mol. Stoichiometry. Stoichiometry. The molar relationship between all of the compounds in a balanced equation. Law of Conservation of Mass
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What is the molar mass for Calcium hydroxide?
A. 57.08 g/mol
B. 74.08 g/mol
C. 64.08 g/mol
D. 27 g/mol
1N2 + 3H2 2NH3
The ratio of Nitrogen to Hydrogen to Ammonia is 1:3:2
N2 + 3H2 2NH3
1. Write the balanced equation
AgNO3 + NaCl AgCl + NaNO3
2. Given and asked for
3. Moles of given
17.0g AgNO3 x 1 mol =
0.100 mol AgNO3
AgNO3 + NaCl AgCl + NaNO3
4. Moles asked for
0.100 mols AgNO3 x 1 mol AgCl =
1 mol AgNO3
0.100 mol AgCl
5. Convert your answer
0.100 mol AgCl x 144 g AgCl =
1 mol AgCl
14.4 g AgCl
How many grams of calcium hydroxide will be needed to react completely with 10.0 g of phosphoric acid (H3PO4) in a double displacement reaction?
1. Balanced equation reaction of 17.0 g silver nitrate with excess sodium chloride solution?
3Ca(OH)2 + 2H3PO4 Ca3(PO4)2 + 6HOH
2. Given & asked for
3. Mols given
10.0 g H3PO4 x 1mol H3PO4 =
0.102 mol H3PO4
4. Mols asked for
0.102 mol H3PO4 x 3 mol Ca(OH)2 =
2 mol H3PO4
0.153 mol Ca(OH)2
5. Convert answer
0.153 mol Ca(OH)2 x 74 g =
1 mol Ca(OH)2
11.3 g Ca(OH)2
What mass of sodium oxide is produced by the reaction of 1.44 g of sodium with oxygen?
4Na + O2 2Na2O
1.44g x 1mol / 23g = 0.0626mol Na
0.0626mol Na x 2Na2O / 4Na = 0.0313mol Na2O
0.0313mol Na2O x 62g / 1mol = 1.94g Na2O
How many kg of lead (II) nitrate will be needed to react with sodium chromate to produce 4.62 kg of lead (II) chromate?
Pb(NO3)2 + Na2CrO4 2NaNO3 + PbCrO4
4620g x 1mol / 323g = 14.3mol PbCrO4
14.3mol PbCrO4 x 1mol / 1mol = 14.3mol Pb(NO3)2
14.3mol Pb(NO3)2 x 331g / 1mol = 4730g(4.73kg)Pb(NO3)2
What quantity of hydrogen gas is formed when 0.85 g of lithium reacts with water? How much lithium hydroxide is produced?
2Li + 2H2O 2LiOH + H2
0.85g Li x 1mol / 7g = 0.12molLi
0.12mol Li x 1H2 / 2Li = 0.060molH2
0.060mol H2 x 2g / 1mol = 0.12g H2 3.0g LiOH
What mass of water is given off when 192 kg of C7H14 burn completely in air? How much oxygen is used?
2C7H14 + 21O2 14CO2 + 14H2O
192,000g C7H14 x 1mol / 98g = 1960mol C7H14
1960mol C7H14 x 14mol / 2mol = 13700mol H2O
13700mol H2Ox 18g / 1mol = 247,000g H2O 658,000g O2