Monday, December 2 nd

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# Monday, December 2 nd - PowerPoint PPT Presentation

Monday, December 2 nd. Warm Up. Review for Final: What is the variable(s) in the expression? What is the constant in the expression? . Grade Check . Grades Left the Semester. 1 more quiz 1 more Warm up(Daily grade) Exponential Test (Test Grade) Semester I Final (Final grade)

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### Monday, December 2nd

Warm Up

Review for Final:

What is the variable(s) in the expression?

What is the constant in the expression?

Check

Grades Left the Semester
• 1 more quiz
• 1 more Warm up(Daily grade)
• Exponential Test (Test Grade)
• Semester I Final (Final grade)
• 3 Weekly Reviews-(daily Grade)
Weekly Review
• We will have three weekly Reviews
• Each will count as a Daily Grade
• They are eligible to replace QUIZ grades 
High School GPA

A: 4.0

B: 3.0

C. 2.0

D. 1.0

F-Receive no Credit. You will have to retake first semester all over again during semester II.

Tutoring

Option 1: Ms. Evans

Tuesday and Thursdays

Before School 6:40-7:00

After School 2:10-2:30

Tutoring

Option 2: Lunch

Tuesday and Thursdays

Either lunch

Go to room 400 FIRST, then to lunch

Tutoring

Option 3: Algebra Department

*Check Schedule in Back

Discussion Question

What’s the difference between exponential growth and exponential decay equations?!

• For compound interest
• annually means “once per year” (n = 1).
• quarterly means “4 times per year” (n =4).
• monthly means “12 times per year” (n = 12).

Example #1

Write a compound interest function to model each situation. Then find the balance after the given number of years.

\$1200 invested at a rate of 2% compounded quarterly; 3 years.

Step 1 Write the compound interest function for this situation.

Write the formula.

Substitute 1200 for P, 0.02 for r, and 4 for n.

= 1200(1.005)4t

Simplify.

Step 2 Find the balance after 3 years.

A = 1200(1.005)4(3)

Substitute 3 for t.

= 1200(1.005)12

Use a calculator and round to the nearest hundredth.

≈ 1274.01

The balance after 3 years is \$1,274.01.

Example #2

Write a compound interest function to model each situation. Then find the balance after the given number of years.

\$15,000 invested at a rate of 4.8% compounded monthly; 2 years.

Step 1 Write the compound interest function for this situation.

Write the formula.

Substitute 15,000 for P, 0.048 for r, and 12 for n.

= 15,000(1.004)12t

Simplify.

Step 2 Find the balance after 2 years.

Substitute 2 for t.

A = 15,000(1.004)12(2)

Use a calculator and round to the nearest hundredth.

= 15,000(1.004)24

≈ 16,508.22

The balance after 2 years is \$16,508.22.

Example #3

Write a compound interest function to model each situation. Then find the balance after the given number of years.

\$1200 invested at a rate of 3.5% compounded quarterly; 4 years

Step 1 Write the compound interest function for this situation.

Write the formula.

Substitute 1,200 for P, 0.035 for r, and 4 for n.

= 1,200(1.00875)4t

Simplify.

Step 2 Find the balance after 4 years.

A = 1200(1.00875)4(4)

Substitute 4 for t.

= 1200(1.00875)16

Use a calculator and round to the nearest hundredth.

 1379.49

The balance after 4 years is \$1,379.49.

Lesson Summary

Write a compound interest function to model each situation. Then find the balance after the given number of years.

1. The number of employees at a certain company is 1440 and is increasing at a rate of 1.5% per year. Write an exponential growth function to model this situation. Then find the number of employees in the company after 9 years.

y = 1440(1.015)t; 1646

2. \$12,000 invested at a rate of 6% compounded quarterly; 15 years

A = 12,000(1 + .06/4)4t, =\$29,318.64