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Photoelectric Effect g absorbed by material, electron ejected

Basic Physics Processes in a Sodium Iodide (NaI) Calorimeter. NaI is a “scintillator”. As a charged particle travels through the NaI it loses energy. The energy lost by the charged particle is absorbed by the NaI molecules and puts

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Photoelectric Effect g absorbed by material, electron ejected

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  1. Basic Physics Processes in a Sodium Iodide (NaI) Calorimeter NaI is a “scintillator”. As a charged particle travels through the NaI it loses energy. The energy lost by the charged particle is absorbed by the NaI molecules and puts the NaI molecules into an excited state. NaI gives off light (“scintillates”) when it de-excites back to the ground state. The amount of light given off by NaI is proportional to the amount energy absorbed. The light yield is ~ 1 photon produced per 100 eV deposited in NaI Photoelectric Effect g absorbed by material, electron ejected Compton Scattering ge-→ge- “elastic scattering” Pair Production g→e+e- creates anti-matter g g g e- e+ e- e- g NaI hv > 10 MeV g-ray must have E>2me 0.05 < hv < 10 MeV hv < 0.05 MeV

  2. How do we get a PEAK in our energy spectrum ? A peak in the energy spectrum corresponds to the case when all of the g-ray’s energy is absorbed in the NaI calorimeter. peaks g perfect energy resolution all g energy totally absorbed actual energy resolution not all g energy totally absorbed g g g e+ e- e- e- Compton scatter followed by photoelectric effect Photoelectric effect and electron stops in NaI. Pair production e- is absorbed in NaI e+ annihilates into 2 g’s g’s undergo photoelectric effect

  3. Cs137 g-ray Spectrum Cs137 b decay b decay gives off electrons with a range of energies Emax = 514 keV, 1170 keV g decay gives off a monchromatic photon E = 662 keV energy b decay Eg=662keV forward scattered electron b decay g 1800 backscatter K-shell x-rays Eg~35 keV Eg=662keV photopeak e- 1800 backscatter Eg=184keV Compton scatterings Compton Edge

  4. Co60 and Na22 Both Co60 and Na22 have complicated spectra since their g’s have enough energy to undergo pair production. Will have “escape” peaks from positron annihilation E=Eg-(rest energy of electron) E=Eg-2x(rest energy of electron) Co 60 b decay g g energy Eg=1172 keV e+ e+ e- e- Eg=1333 keV Na 22 Na 22 gives off a positron which will annihilate and produce 2 g’s. But only one g will be detected! positron bdecay e+ energy Eg=1277 keV e-

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