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# Big POPa - PowerPoint PPT Presentation

Big POPa. Group Members: Evan Hudspeth Stuart Haase Charlie Gang Dave Dickenson. Initial Step. Spin It!. τ= F·r F= m·a m= 0.032 slugs r= 0.167 ft The acceleration was found by constant acceleration equation: V2 2 =V1 2 +2ad d is the distance the ball travels which is 1.417 ft.

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## PowerPoint Slideshow about ' Big POPa' - jara

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Presentation Transcript

Group Members:

Evan Hudspeth

Stuart Haase

Charlie Gang

Dave Dickenson

• τ=F·r F=m·a

• m= 0.032 slugs

• r= 0.167 ft

• The acceleration was found by constant acceleration equation:

• d is the distance the ball travels which is 1.417 ft.

• V2= 4.79 ft/s V1= 0 ft/s

• (4.79 ft/s)2= (0 ft/s)2 + 2a(1.417 ft)

• a= 8.13 ft/s2

• F= (0.032 slugs) (8.13 ft/s2) = 0.026 lb

• τ = (0.167 ft)(0.026 lb)= 0.0043 ft-lb

• mgh = ½mV2

• mass cancels out in the calculation

• g= 32.2 ft/s2

• h= 0.875 ft

• (32.2 ft/s2)(0.0875 ft)= ½V2

• V= 7.51 ft/s

• mpd+mbd/mp+mb

• (.00014slugs)(1.29ft)+(.0013slugs)(.75ft)/(.00014slugs)+(.0013slugs)

• Center of mass=0.88ft from tied side

• V1= 0 ft/s

• a= 32.2 ft/s2

• d=1.29 ft

• v22=(0 ft/s) + 2(32.2 ft/s2)(1.29 ft)

• V2= 9.11 ft/s

• X: V1 (found with conservation of energy)= 1.036 ft/s

• V2= 0 ft/s

• d= 0.083 ft

• a= -6.47 ft/s2

.

Perfectly inelastic collision

mball (Vball) + mcup(Vcup)= (mball+mcup)Vfinal

mball=0.0015 slugs

Vball=9.11 ft/s

mcup=9.01*10-4

Vcup=0 ft/s

(0.0015slugs)(9.11 ft/s)+0=(0.0024 slugs) Vfinal

Vfinal= 5.69 ft/s

• Initial Ramp

• Hitting the cup reliably

• Popping the balloon (placement of needle)

• Working out minor kinks