Birthday Problem. The probability of 2 people having the same birthday in a room of 41 people is 90%. To randomly select ___ birthdays, randInt (1, 365, __) L1:SortA(L1) This will sort the day in increasing order; scroll through the list to see duplicate birthdays. Repeat many times.
This will sort the day in increasing order; scroll through the list to see duplicate birthdays. Repeat many times.
: Prompt N
: 1- (prod((seq((366-X)/365, X, 1, N, 1))
Find the probability that the children are:
(c) exactly two boys or exactly two girls
(d) at least one child of each sex
The union of a collection of events:
The Additional Rule of Disjoint Events:
In a statistics class there are 18 juniors and 10 seniors; 6 of the seniors are females, and 12 of the juniors are males. If a student is selected at random, find the probability of selecting
2) P(neither is made partner)
3) P(Deborah makes partner and Matthew does not)
3) P(Matthew makes partner and Deborah does not).
2) P(A and B)
3) P(B given A)
Call a household prosperous if its income exceeds $100,000. Call the household educated if the householder completed college. Select an American household at random, and let A be the event that the selected household is prosperous and B the event that it is educated. According to the Current Population Survey, P(A) = 0.138, P(B) = 0.261, and the probability that a household is both prosperous and educated is P(A and B) = 0.082.
70% of people buy Brand 1 DVD player. 30% buy Brand 2. Of those who buy a DVD player, 20% of those who buy Brand 1 also get the extended warranty and 40% of those who buy Brand 2 get it. Make a tree diagram and then find the following: