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Physics 1A, Section 6. October 30, 2008. Section Business. Section 6 for Monday, Nov. 3 is canceled . Visit another section if you wish. Office hour for Nov. 4 is unchanged. Look for graded Quiz 2 in Section 6 box in Bridge, noon Monday at the earliest. Quiz Problem 49. Quiz Problem 49.

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physics 1a section 6

Physics 1A, Section 6

October 30, 2008

section business
Section Business
  • Section 6 for Monday, Nov. 3 is canceled.
    • Visit another section if you wish.
    • Office hour for Nov. 4 is unchanged.
    • Look for graded Quiz 2 in Section 6 box in Bridge, noon Monday at the earliest.
quiz problem 491
Quiz Problem 49
  • Answer:
  • {[k3 + (k1-1 + k2-1)-1]-1 + k4-1]-1
energy conservation
Energy Conservation
  • Energy is conserved: K + U + heat + … = constant
  • Sometimes, mechanical energy is conserved:
    • K + U = mechanical energy = constant
      • Example: ½ mv2 + mgh = constant
    • This often allows a quick solution of a difficult problem.
energy conservation1
Energy Conservation
  • Energy is conserved: K + U + heat + … = constant
  • Sometimes, mechanical energy is conserved:
    • K + U = mechanical energy = constant
      • Example: ½ mv2 + mgh = constant
    • This often allows a quick solution of a difficult problem.
  • However, in other cases, mechanical energy is not conserved, so K + U  constant:
    • friction: Energy is lost to heat.
    • inelastic collision: Energy is lost to heat.
    • This is the same thing as saying the force can’t be described by a potential energy; the force is a function of some variable other than position.
energy conservation2
Energy Conservation
  • Energy is conserved: K + U + heat + … = constant
  • Sometimes, mechanical energy is conserved:
    • K + U = mechanical energy = constant
      • Example: ½ mv2 + mgh = constant
    • This often allows a quick solution of a difficult problem.
  • However, in other cases, mechanical energy is not conserved, so K + U  constant:
    • friction: Energy is lost to heat.
    • inelastic collision: Energy is lost to heat.
    • This is the same thing as saying the force can’t be described by a potential energy; the force is a function of some variable other than position.
    • In some of those cases, one can resort to using the force to calculate the energy added to the system:

energy input = W = ∫F•ds

quiz problem 501
Quiz Problem 50
  • Answer:
  • v = sqrt(2gh)
  • F = -kx – mmg, to the right
  • W = -kxs2/2 – mmgxs
  • Wf = 2mmgxs
  • h’ = h – 2mxs
  • xs = [-mmg + sqrt(m2m2g2+2kmgh)]/k
thursday november 6

Monday, November 3:

Thursday, November 6:
  • Section 6 is canceled.
  • Tuesday office hour as usual.
  • Quiz Problem 38 (momentum/collisions)
  • Optional, but helpful, to look at these in advance.
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