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AP Multiple Choice 2004 answers. 1. 72% For which of the following motions of an object must the acceleration always be zero? I. Any motion in a straight line II. Simple harmonic motion III. Any motion in a circle a. I only b. II only c. III only

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  • 1. 72% For which of the following motions of an object must the acceleration always be zero?

  • I. Any motion in a straight line

  • II. Simple harmonic motion

  • III. Any motion in a circle

  • a. I only

  • b. II only

  • c. III only

  • d. Either I or III, but not II

  • e. None of these motions guarantees zero acceleration.


  • 2. 43% A rope of negligible mass supports a block that weighs 30 N, as shown above. The breaking strength of the rope is 50 N. The largest acceleration that can be given to the block by pulling up on it with the rope without breaking the rope is most nearly

  • a. 6 m/s2b. 6.7 m/s2 c. 10 m/s2 d. 15 m/s2 e. 16.7 m/s2


  • 3. 37% A compressed spring mounted on a disk can project a small ball. When the disk is not rotating, as shown in the top view above, the ball moves radially outward. The disk then rotates in a counterclockwise direction as seen from above, and the ball is projected outward at the instant the disk is in the position shown above. Which of the following best shows the subsequent path of the ball relative to the ground?




  • A sphere of mass is suspended from a scale and submerged in a liquid. If the reading on the scale is 3 N, then the buoyant force that the fluid exerts on the ml, which is attached to a spring, is displaced downward from its equilibrium position as shown above left and released from rest. A sphere of mass m2, which is suspended from a string of length l, is displaced to the right as shown above right and released from rest so that it swings as a simple pendulum with small amplitude. Assume that both spheres undergo simple harmonic motion

  • 6. 64% Which of the following is true for both spheres?

  • a. The maximum kinetic energy is attained as the sphere passes through its equilibrium position.

  • b. The maximum kinetic energy is attained as the sphere reaches its point of release.

  • c. The minimum gravitational potential energy is attained as the sphere passes through its equilibrium

  • position.

  • d. The maximum gravitational potential energy is attained when the sphere reaches its point of release.

  • e. The maximum total energy is attained only as the sphere passes through its equilibrium position.


a.


  • 8.58% A block attached to the lower end of a vertical spring oscillates up and down. If the spring obeys Hooke's law, the period of oscillation depends on which of the following?

  • I. Mass of the block

  • II. Amplitude of the oscillation

  • III. Force constant of the spring

  • a. I only b. II only c. III only d. I and II e. I and III


  • 9.75% An empty sled of mass oscillates up and down. If the spring obeys Hooke's law, the period of oscillation depends on which of the following?M moves without friction across a frozen pond at speed vo. Two objects are dropped vertically into the sled one at a time: first an object of mass m and then an object of mass 2m. Afterward the sled moves with speed vf . What would be the final speed of the sled if the objects were dropped into it in reverse order?

  • a. vf /3 b. vf /2 c. vf d. 2vf e. 3vf




  • 12. 37% Two blocks of steel, the first of mass 1 kg and the second of mass 2 kg, are in thermal equilibrium with a third block of aluminum of mass 2 kg that has a temperature of 400 K. What are the respec­tive temperatures of the first and second steel blocks?

  • a. 400 K and 200 K b. 200 K and 400 K c. 400 K and 400 K

  • d. 800 K and 400 K e. None of the above


  • 13. 30% An ideal gas may be taken from one state to another state with a different pressure, volume, and temperature along several different paths. Quantities that will always be the same for this process, regardless of which path is taken, include which of the following?

  • I. The change in internal energy of the gas

  • II. The heat exchanged between the gas and its surroundings

  • III. The work done by the gas


  • 14. 49% Two parallel wires, each carrying a current state with a different pressure, volume, and temperature along several different paths. Quantities that will always be the same for this process, regardless of which path is taken, include which of the following?I, repel each other with a force F. If both currents are doubled, the force of repulsion is

  • a. 2F b. F c. 4Fd. F e. 8F


  • 15. 29% The hollow metal sphere shown above is positively charged. Point C is the center of the sphere and point P is any other point within the sphere. Which of the following is true of the electric field at these points?

  • a. It is zero at both points.

  • b. It is zero at C, but at P it is not zero and is directed inward.

  • c. It is zero at C, but at P it is not zero and is directed outward.

  • d. It is zero at P, but at C it is not zero.

  • e. It is not zero at either point.


  • 16. 36% The total capacitance of several capacitors in parallel is the sum of the individual capacitances for which of the following reasons?

  • a. The charge on each capacitor depends on its capacitance, but the potential difference across each is

  • the same.

  • b. The charge is the same on each capacitor, but the potential difference across each capac­itor

  • depends on its capacitance.

  • c. Equivalent capacitance is always greater than the largest capacitance.

  • d. Capacitors in a circuit always combine like resistors in series.

  • e. The parallel combination increases the effec­tive separation of the plates.


  • 17. 22% A wire of length parallel is the sum of the individual capacitances for which of the following reasons?L and radius r has a resistance R. What is the resistance of a second wire made from the same material that has a length L/2 and a radius r/2 ?

  • a. 4R b. 2R c. R d. R/2 e. R/4



  • Charges motor that lifts a 9 kg mass against gravity at an average velocity of 0.5 m/s is most nearly‑Q and +Q are located on the x‑ and y‑axes, respectively, each at a distance d from the origin O, as shown above.

  • 19. 48% What is the direction of the electric field at the origin O ?

  • a. b.

  • c. d. e.



  • 21. 57% An electron origin e and a proton p are simultaneously released from rest in a uniform electric field E, as shown above. Assume that the particles are sufficiently far apart so that the only force acting on each particle after it is released is that due to the electric field. At a later time when the particles are still in the field, the electron and the proton will have the same

  • a. direction of motion b. speed

  • c. displacement d. magnitude of acceleration

  • e. magnitude of force acting on them



  • 23. 81% Which of the following will occur if the average speed of the gas molecules in a closed rigid container is increased?

  • a. The density of the gas will decrease. b. The density of the gas will increase.

  • c. The pressure of the gas will increase. d. The pressure of the gas will decrease.

  • e. The temperature of the gas will decrease.



  • 25. 57% curvature at point The frequencies of the first two overtones (second and third harmonics) of a vibrating string are f and 3f /2. What is the fundamental frequency of this string?

  • a. f /3 b. f /2 c. f d. 2f e. 3f

  • .


  • 26. 37% An object is placed in front of a converging thin lens at a distance from the center of the lens equal to half the focal length. Compared to the object, the image is

  • a. upright and larger b. upright and smaller c. inverted and larger

  • d. inverted and smaller

  • e. inverted and the same size






  • 31. 85% How does an air mattress protect a stunt person landing on the ground after a stunt?

  • a. It reduces the kinetic energy loss of the stunt person.

  • b. It reduces the momentum change of the stunt person.

  • c. It increases the momentum change of the stunt person.

  • d. It shortens the stopping time of the stunt person and increases the force applied during the landing.

  • e. It lengthens the stopping time of the stunt person and reduces the force applied during the landing.


A horizontal, uniform board of weight 125 N and length 4 m is supported by vertical chains at each end. A person weighing 500 N is sitting on the board. The tension in the right chain is 250 N.

  • 32. 75% What is the tension in the left chain?

  • a. 250 N b. 375 N c. 500 N d. 625 N

  • e. 875 N


  • 33. 52% is supported by vertical chains at each end. A person weighing 500 N is sitting on the board. The tension in the right chain is 250 N.How far from the left end of the board is the person sitting?

  • a. 0.4 m b. 1.5 m c. 2 m d. 2.5 m

  • e. 3 m


Questions 34‑35 relate to the photoelectric effect. For each question, choose an answer from the following graphs

  • .




  • 36. 28% Which of the following statements about the number of protons Z and the number of neutrons N in stable nuclei is true?

  • a. All stable nuclei have Z= N.

  • b. Only heavy stable nuclei have Z = N.

  • c. Heavy stable nuclei tend to have Z < N.

  • d. All light stable nuclei have Z < N.

  • e. All light stable nuclei have Z > N.


  • 37. 44% Each of the beakers shown above is filled to the same depth h with liquid of density p. The area A of the flat bottom is the same for each beaker. Which of the following ranks the beakers according to the net downward force exerted by the liquid on the flat bottom, from greatest to least force?

  • a. I, III, II, IV

  • b. I, IV, III, II

  • c. II, III, IV, I

  • d. IV, III, I, II

  • e. None of the above; the force on each is the same.


  • 38. 36% A T‑shaped tube with a constriction is inserted in a vessel containing a liquid, as shown above. What happens if air is blown through the tube from the left, as shown by the arrow in the diagram?

  • a. The liquid level in the tube rises to a level above the surface of the liquid surrounding the tube.

  • b. The liquid level in the tube falls below the level of the surrounding liquid.

  • c. The liquid level in the tube remains where it is.

  • d. The air bubbles out at the bottom of the tube.

  • e. Any of the above depending on how hard the air flows


  • 39. 12% A spring scale calibrated in kilograms is used to determine the density of a rock specimen. The reading on the spring scale is 0.45 kg when the specimen is suspended in air and 0.36 kg when the specimen is fully submerged in water. If the density of water is 1000 kg/m3, the density of the rock specimen is

  • a. 2.0 x 102 kg/m3

  • b. 8.0 x 102 kg/m3

  • c. 1.25 x 103 kg/m3

  • d. 4.0 x 103 kg/m3

  • e. 5.0 x 103 kg/m3


  • 40. 56% Two objects, determine the density of a rock specimen. The reading on the spring scale is 0.45 kg when the specimen is suspended in air and 0.36 kg when the specimen is fully submerged in water. If the density A and B, initially at rest, are "exploded" apart by the release of a coiled spring that was compressed between them. As they move apart, the velocity of object A is 5 m/s and the velocity of object B is ‑2 m/s. The ratio of the mass of object A to the mass of object B, mA/mB, is

  • a. 4/25 b. 2/5 c. 1/1

  • d. 5/2

  • e. 25/4


  • 41. 65% The cart of mass 10 kg shown above moves without frictional loss on a level table. A 10 N force pulls on the cart horizontally to the right. At the same time, a 30 N force at an angle of 60° above the horizontal pulls on the cart to the left. What is the magnitude of the horizontal acceleration of the cart? a. 0.5 m/s2 b. 1.6 m/s2

  • c. 2.0 m/s2

  • d. 2.5 m/s2

  • e. 2.6 m/s2



  • 43. 29% A simple pendulum and a mass hanging on a spring both have a period of 1 s when set into small oscillatory motion on Earth. They are taken to Planet X, which has the same diameter as Earth but twice the mass. Which of the following state­ments is true about the periods of the two objects on Planet X compared to their periods on Earth?

  • a. Both are shorter.

  • b. Both are the same.

  • c. Both are longer.

  • d. The period of the mass on the spring is shorter, that of the pendulum is the same.

  • e. The period of the pendulum is shorter; that of the mass on the spring isthe same.




  • 45. 45% The electric potential at point apart, as shown above. The lower plate is at a potential of 2 V with respect to ground. The upper plate is at a potential of 10 V with respect to ground. Point P is

  • a. 10 V

  • b. 8 V

  • c. 6 V

  • d. 4 V

  • e. 2 V


  • 46. 18% The magnitude of the electric field at point apart, as shown above. The lower plate is at a potential of 2 V with respect to ground. The upper plate is at a potential of 10 V with respect to ground. Point P is

  • a. 800 V/m

  • b. 600 V/m

  • c. 400 V/m

  • d. 200 V/m

  • e. 100 V/m


  • 47. 27% Two conducting wire loops move near a very long, straight conducting wire that carries a current I. When the loops are in the positions shown above, they are moving in the directions shown with the same constant speed v . Assume that the loops are far enough apart that they do not affect each other. Which of the following is true about the induced electric currents, if any, in the loops?

  • Loop lLoop 2

  • a. No current No current

  • b. No current Counterclockwise direction

  • c. Clockwise direction No current

  • d. Clockwise direction Clockwise direction

  • e. Counterclockwise direction Clockwise direction



  • 49. 64% How do the currents straight conducting wire that carries a current I1, I2, and 13 compare?

  • a. I1 > I2 > I3 b. I1 > I3 > I2

  • c. I2 > I1 > I3

  • d. I3 > I1 > I2

  • e. I3 > I2 > I1


  • A light ray straight conducting wire that carries a current R in medium I strikes a sphere of medium II with angle of incidence θ, as shown above. The figure shows five possible subsequent paths for the light ray.

  • 50. 25% Which path is possible if medium I is air and medium II is glass?

  • a. A

  • b. B

  • . C c

  • d. D

  • e. E


  • 51. 23 % straight conducting wire that carries a current Which path is possible if medium I is glass and medium II is air?

  • a. A

  • b. B

  • c. C

  • d. D

  • e. E


  • 52. 32%Two fire trucks have sirens that emit waves of the same frequency. As the fire trucks approach a person, the person hears a higher frequency from truck X than from truck Y. Which of the following statements about truck X can be correctly inferred from this information?

  • I. It is traveling faster than truck Y.

  • II. It is closer to the person than truck Y.

  • III. It is speeding up. and truck Y is slowingdown.

  • a. I only

  • b. III only

  • c. I and II only

  • d. II and III only

  • e. I, II, and III


  • 53. 9% A thin film with index of refraction n same frequency. As the fire trucks approach a person, the person hears a higher frequency from truck f separates two materials, each of which has an index of refraction less than nf. A monochromatic beam of light is incident normally on the film, as shown above. If the light has wavelength λ within the film, maximum constructive interference between the incident beam and the reflected beam occurs for which of the following film thicknesses?

  • a. 3λ

  • b. 2λ

  • c. λ

  • d. λ/2

  • e. λ/4


  • 54. same frequency. As the fire trucks approach a person, the person hears a higher frequency from truck 49%An object is placed on the axis of a converging thin lens of focal length 2 cm, at a distance of 8 cm from the lens. The distance between the image and the lens is most nearly

  • a. 0.4 cm

  • b. 0.8 cm

  • c. 1.6 cm

  • d. 2.0 cm

  • e. 2.7 cm


  • 55. 15% A large lens is used to focus an image of an object onto a screen. If the left half of the lens is covered with a dark card, which of the following occurs?

  • a. The left half of the image disappears.

  • b. The right half of the image disappears.

  • c. The image becomes blurred.

  • d. The image becomes dimmer.

  • e. No image is formed.



  • 57.41% A gas with a fixed number of molecules does 32 J of work on its surroundings, and 16 J of heat are transferred from the gas to the surroundings. What happens to the internal energy of the gas?

  • a. It decreases by 48 J. b. It decreases by 16 J.

  • c. It remains the same. d. It increases by 16 J.

  • e. It increases by 48 J.


  • 58. 23% When work on its surroundings, and 16 J of heat are transferred from the gas to the surroundings. What happens to the internal energy of the gas?10 B is bombarded by neutrons, a neutron can be absorbed and an alpha particle (4He) emitted. If the 10 B target is stationary, the kinetic energy of the reaction products is equal to the

  • a. kinetic energy of the incident neutron

  • b. total energy of the incident neutron

  • c. energy equivalent of the mass decrease in the reaction

  • d. energy equivalent of the mass decrease in the reaction, minus the kinetic energy of the incident neutron e. energy equivalent of the mass decrease in the reaction, plus the kinetic energy of the incident neutron


  • 59. 34% The nuclide emits an electron and becomes nuclide work on its surroundings, and 16 J of heat are transferred from the gas to the surroundings. What happens to the internal energy of the gas?X. Which of the following gives the mass number and atomic number of nuclide X ?

  • Mass Atomic

  • Number Number

  • a. 210 80

  • b. 210 81

  • c. 213 83

  • d. 214 81

  • e. 214 83



  • An object of mass wavelength 4 m. Which of the following is the best estimate of the number of photons it emits per second?m is initially at rest and free to move without friction in any direction in the xy‑plane. A constant net force of magnitude F directed in the +x direction acts on the object for 1 s. Immediately thereafter a constant net force of the same magnitude F directed in the +y direction acts on the object for 1 s. After this, no forces act on the object.


61.69% Which of the following vectors could represent the velocity of the object at the end of 3 s, assuming the scales on the x and y axes are equal.


62. 25% Which of the following graphs best represents the kinetic energy K of the object as a function of time?


  • 63. 7% The two blocks of masses kinetic energy M and 2M shown above initially travel at the same speed v but in opposite directions. They collide and stick together. How much mechanical energy is lost to other forms of energy during the collision?

  • a. Zero b. c. d. . e.



  • 65. 13% A particle of charge about an axis perpendicular to the field. as shown above. How many times is the induced current in the loop reversed if the loop makes 3 complete revolutions from the position shown?Q and mass m is accelerated from rest through a potential difference V, attain­ing a kinetic energy K. What is the kinetic energy of a particle of charge 2Q and mass m/2 that is accelerated from rest through the same potential difference?

  • a. 4

  • b. 2

  • c. K d. 2K


  • 66. 40% The diagram above shows electric field lines in an isolated region of space containing two small charged spheres, Y and Z Which of the following statements is true?

  • a. The charge on Y is negative and the charge on Z is positive.

  • b. The strength of the electric field is the same everywhere.

  • c. The electric field is strongest midway between Y and Z.

  • d. A small negatively charged object placed at point X would tend to move toward the right.

  • e. Both charged spheres Y and Z carry charge of the same sign.




  • 69.27% As shown above, a positively charged particle moves to the right without deflection through a pair of charged plates. Between the plates are a uniform electric field E of magnitude 6.0 N/C and a uniform magnetic field B of magnitude 2.0 T, directed as shown in the figure. The speed of the particle is most nearly

  • a. 0.33 m/s

  • b. 0.66 m/s

  • c. 3.0 m/s

  • d. 12 m/s

  • e. 18 m/s



Ap multiple choice answers 2004

AP Multiple Choice Answers 2004 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

Remember: Multiple Choice is Not Multiple Guess, Work out the answers


1. charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E. None of these – THEY CAN ALL INCLUDE ACCELERATION


2 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B 6.7 m/s2

  • T = mg + ma

  • 50 N = 30 N + (3 kg) (a)

  • 20 N = 3 a

  • a= 20/3 = 6.7 m/s2


3 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E.


4 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E.

  • None of the above


5 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • WEIGHT OF 0.4 KG = 4.0 N

  • Fnet = mg – FBuoy

  • 3 N = 4 N – FBuoy

  • FBuoy = 4 N – 3 N


6 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • The maximum kinetic energy is attained as the sphere passes through its equilibrium position. – because this is where the maximum velocity is.


7 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • Ts = Tp

  • 2 (L/g) = 2 (m1 /K)

  • (L/g) = (m1 /K)

  • (K) = (m1 g/L)


8 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • Ts = 2(m/K)

  • mass and force constant only

  • I and III only


9 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • The same vf


10 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • F1 = GM1 m2 /r12

  • F2 = G2M1 m2 /(2r1) 2

  • F2 = G2M1 m2 /(4 r12)

  • F2 = ½ G M1 m2 /r12 = ½ F1 =½ 500 N = 250 N


11 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • v = d/t = 8 m – 2 m / 1 s = 6m/s


12 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • Thermal equilibrium MEANS temperature is the same!


13 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

P

V

U = Q + W

Work done = area under the curve

Only the change in internal energy is the same


14 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • F = 0 I1 I2/2  r

  • F1 = 0 I2 /2  r

  • F2 = 0 (2 I)2 /2  r

  • F2 = 0 4 I2 /2  r

  • F2 = 4 F1


15 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • Electric field is zero throughout a sphere

P

C

Electric field is zero throughout a sphere, all electric charge is on the surface and the forces are in equilibrium, the sphere is at equipotential.


16 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

V

  • A

Q1

Q2

Q3

The charge on each capacitor depends on its capacitance, but the potential difference across each is the same.


17 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • R1 =  L1 /A1 =  L1 /r1 2

  • R2 =  ½ L1 /A2 =  ½ L1 / (r1 /2)2

  • R2 =  ½ L1 /( (r1 /2)2 ) =  ½ L1 /( (r12 /4))

  • R2 = 4  ½ L1 / (r1)2 = 2  L1 / r1 2 = 2 R1


18 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • Efficiency = Pout/Pin x 100%

  • Eff = Fv/IV x 100%

  • Eff = 90 N x 0.5 m/s/(0.5 A x 120 V) x 100%

  • Eff = 45/60 x 100% = 75 %


19 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

+Q

-Q


20 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

ER = ((KQ/d2)2 + (KQ/d2)2) = (2(KQ/d2 )2) = 2 (KQ/d2)

E = KQ/d2

E = KQ/d2


21 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • F = QE


22 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • Final Lplate = L0plateT

  • Final Lhole = L0holeT

  • Divide the two

    Lplate/ Lhole = L0 plate/ L0hole

    1.01/ Lhole = 1.00/ 0.1

    Lhole = 1.01 x 0.1/1.00

    Lhole =0.101

    0.101 m


23 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • PV = nRT = 1/3 Nmv2


24 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • F=R/2


25 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • First three harmonics fundamental, first overtone, and second overtone /2, , 3/2


26 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • When object is closer than the focal length of a converging lens then it acts as a magnifying lens therefore the image is virtual, upright, and magnified.


27 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • v=f

  •  = v/f = 3 x 108 / 100 x 106

  • 3.0 m


28 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • They both give rise to interference effects


29 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • Slope = 25-5/4 = 5N/s


30 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • Increase in momentum = impulse

  • mv = Ft = area under curve = 5 x 4 + ½ x 20 x 4 = 60 N · s


31 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • mv = Ft

  • Increase t reduces F for the same change in momentum


32 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

F

  • B

250 N

125 N

500 N

F + 250 N = 500 N + 125 N

F = 625 – 250 N = 375 N


33 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

F

  • B

250 N

125 N

d

500 N

Taking Torques about the left end

500 x d + 125 x 2 = 250 x 4

500d = 1000 – 250

D = 750/500 = 1.5 m


34 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • Kmax = hf - 

Kmax

f


35 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

Current

(Amps)

Intensity P/A (W/m)


36 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • Stable heavy nuclei have more neutrons N than protons Z to prevent electrostatic repulsion between the protons so the answer is Z < N.


37 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • F = PA = gHA

  • Same H same A means same force


38 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • Bernoulli’s Equation:

  • P + ½  v2 + gh = a constant

  • If v increases pressure decreases for the same height


39 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • Fnet = mg – FBuoy

  • 3.6 N = 4.5 N – FBuoy

  • F Buoy = 4.5 – 3.6 = 0.9 N

  • F Buoy = water g Vrock

  • 0.9 N = 1000 x 10 x Vrock

  • Vrock= 0.9 N / 1000 x 10 = 9 x 10-5 m3

  • mg = rock g Vrock

  • 4.5 N = rock10 x 9 x 10-5

  • rock = 4.5 N /(10 x 9 x 10-5) = 5000 kg/m3


40 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • Conservation of momentum

  • 0 = mAvAf + mB vBf

  • 0 = mA 5 m/s + mB (-2 m/s)

  • 2 mB = 5 mA

  • 2/5 = mA/mB


41 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

10 N

30 N Cos 60. = 15 N

F net = 5 N

a =F/m = 5 N/ 10 kg = 0.5 m/s2


42 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • v = 2R/T

  • ac = v2/R = (2R/T)2/R = 42R2/(T2R) = 42R/(T2)


43 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • g1 = GM1 /R12

  • g2 = G2M1 /R12 = 2 g1

  • Tpendulum1 = 2(L/g1)

  • Tpendulum2 = 2(L/g2) = 2(L/2g1)

  • period is shorter by  ½

  • Tspring = 2(m/K) not affected by gravity


44 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • Centripetal force is always directed to the center of the circle


45 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

10 V

0.04 m

potential difference = 8.0 V

P 0.01 m

2 V

P is quarter way up so potential is quarter way up = 4.0 V


46 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • E = V/d = 8.0 V/ 0.04 m = 200 V/m


47 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

Loop 2

Loop 1

Magnetic field B from wire going into page (Use right hand thumb rule)

Loop 2 is not changing magnetic field so no induced current emf = BA/t

Loop 1 is going in direction of reduced magnetic field so direction of induced current will be such as to oppose the change causing it. So needs more magnetic field into the page – clockwise using right hand thumb rule


48 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • First find resistance of parallel circuit 1/RT = 1/R1 +1/R2 = 1/ 2000 + 1/6000 = 3/6000 + 1/6000 = 4/6000

  • so RT = 6000/4 = 1 500 

  • Total circuit resistance = 2 500 + 1500 =

  • 4 000 

  • I = V/R = 12 V/ 4000 = 3/1000 = 3milliAmps


49 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • Current I1 is greatest followed by I2 followed by I3


50 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • bent towards normal going in and away from normal coming out


51 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • bent away from normal going in and towards normal coming out


52 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • Doppler effect X traveling faster than truck Y


53 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

Phase reversal

No Phase reversal

If thickness is equal to λ/4 then waves will be back in phase by the time the second wave reaches the top therefore constructive interference


54 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • 1/f = 1/si + 1/so

  • 1/si = 1/f - 1/so

  • 1/si = ½ - 1/8 = 4/8 – 1/8 = 3/8

  • si = 8/3 = 2.7 cm


55 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • The image becomes dimmer


56 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • Q/t = KAT/L

  • Decrease q by decreasing A and T


57 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • U = Q + W = -16 -32 = -48 J lost to surroundings


58 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • E = mc2

  • Change in mass goes to energy + initial kinetic energy


59 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • 21482 Pb = 21483 X + 0-1

  • Numbers must be equal on both sides


60 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • Energy of one photon E = hf = hc/λ= 1.99 x 10-25/4 m = 0.5 x 10-25 = 5 x 10-26.

  • Number of photons in 50 000 Watts or Joules per second = 5 x 104/5 x 10-26

  • = 1 x 1030


61 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • velocity against time


62 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • B

  • Kinetic energy against time (K proportional to v2)


63 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • m1 vi1 + m1 vi2 = m1 vf1 + m2 vf2

  • Mv-2Mv = 3Mvf

  • v – 2v = 3 vf

  • -2v/3 = vf

  • ½ m1 vi12 - ½ m2 vf22 = ½ m1 vf12 + ½ m1 vf22 + Klost

  • ½ M v 2 + ½ 2M v 2 = ½ 3M1 (v/3) 2 + K

  • 3/2 M v2 = 3 M v2/18 + K

  • 3/2 M v2 = 1/6 M v2 + K

  • 3/2 M v2 - 1/6 M v2 = K

  • 9/6 M v2 – 1/6 M v2 = K

  • 8/6 M v2 =K

  • 4/3 M v2 =K


64 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • 6


65 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • Kinetic energy = electrical energy

  • K1 = QV

  • K2 = 2QV = 2 K1


66 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • D

  • Z is negative so electron would be repelled.


67 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

  • Fc = Fg

  • msatellite v2/R = G MEarth msatellite/R2

  • R = GM/v2


68 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • E

  • P =W/t = Fv/t = 900 N x 4 m/s/10s

  • P =3600 W


69 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • C

E

+

B

x

Forcemagnetic =Force Electric

BQv = QE

v = E/B = 6/2 = 3m/s


70 charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly

  • A

  • E = KQ/R2

  • E = 9 x 109 x 4 x10 -6/ 2.02

  • E = 36 x 10 3/ 4.0 = 9 x 103 N/C


The end
THE END charge of 4.0 μC. The electric field at a distance of 2.0 m from the center of the sphere is most nearly


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