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Review of Chemistry 11 PowerPoint PPT Presentation


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Review of Chemistry 11. Prior Knowledge Needed for Chemistry 12. Naming molecules and writing formulas Balancing Chemical Equations Counting Significant figures Calculating with significant figures Mole calculations Basic Stoichiometry. Naming Molecules and Writing Formulas.

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Review of Chemistry 11

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Review

of

Chemistry

11


Prior Knowledge Needed for Chemistry 12

  • Naming molecules and writing formulas

  • Balancing Chemical Equations

  • Counting Significant figures

  • Calculating with significant figures

  • Mole calculations

  • Basic Stoichiometry


Naming

Molecules

and

Writing

Formulas


What do you remember?

Categorize the following according to what elements are involved and the types of intramolecular bonds:

HCl, NaCl, CO2, Cu(ClO) 2, CaO, HF, Ca(OH) 2, HIO3, Sr(NO3) 2, Pb(NO3) 2, AgNO3, KBr, NaOH, N2O3, FeO, CH3COOH,


Analyze each pair (name = formula) and come up with some rules…

Hyroiodic Acid = HI

Nitrous Acid = HNO2

Nitric Acid = HNO3


Copper(II) nitride = Cu(NO3)2

Sodium phosphate = Na2PO4

Gold(II) oxide = AuO


Sulphur diflouride = SF2

Dinitrogen trioxide = N2O3


Balancing

Chemical

Equations

“BCE”


Why?


General Guidelines

  • Balance any polyatomic ions first

  • Balance metals

  • Balance nonmetals

  • Balance “O” and “H” last

  • Recount both sides to make sure!!


Al + O2 Al2O3


C2H6 + O2 CO2 + H2O


Counting

Significant

figures


Answers…

100 = 1

0.001 = 1

0.010 = 2

10.04 = 4

1.0 x 102 = 2

197 = 3

0.0000200910 = 6

100.20 = 5

10.0 = 3

1090 = 3


What are the general rules for what zero’s are significant?


Calculating with Significant Figures


Answers…

Adding and Subtracting…

10.00 + 2.0 = 12.0

36.98 – 0.0013= 36.98

General Rule?


Answers…

Multiplying and Dividing…

190 / 3 = 60

1403 / 7.0 = 2.0 x 102

0.09700 x 1.2 = 0.12

General Rule?


Mole

Calculations


Answer…

How many grams of NaCl are in 4.50 moles of NaCl?

# g NaCl = 4.50 mol x 58.5 g = 263 g NaCl

1 mol

What steps were used to answer this question?


Answer…

How many moles of NH4Br are in 15.87 g of NH4Br?

# mol NH4Br= 15.87g x 1 mol =0.162 mol NH4Br

97.9 g

What steps were used to answer this question?


General Rules…


Basic

Stoichiometry


Answers…

Given the following balanced equation, answer the questions following it:

9Na + 4ZnI2 8NaI + NaZn4

a.) If 2.50 moles of Na are reacted, how many moles of ZnI2 will be consumed?

# mol ZnI2 = 2.50 mol Na x 4 mol ZnI2 = 1.11 mol ZnI2

9 mol Na

b.) If you completely react 526.68 g of ZnI2, what mass of NaZn4 will be produced?

# g NaZn4 = 526.68g of ZnI2x 1 mol ZnI2 x 1 mol NaZn4 x 284.6g NaZn4 = 117.4g NaZn4

319.2 g ZnI2 4 mol ZnI2 1 mol NaZn4


What steps were taken to answer these questions?


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