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Review of Chemistry 11. Prior Knowledge Needed for Chemistry 12. Naming molecules and writing formulas Balancing Chemical Equations Counting Significant figures Calculating with significant figures Mole calculations Basic Stoichiometry. Naming Molecules and Writing Formulas.

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Review

of

Chemistry

11


Prior knowledge needed for chemistry 12
Prior Knowledge Needed for Chemistry 12

  • Naming molecules and writing formulas

  • Balancing Chemical Equations

  • Counting Significant figures

  • Calculating with significant figures

  • Mole calculations

  • Basic Stoichiometry


Naming

Molecules

and

Writing

Formulas


What do you remember
What do you remember?

Categorize the following according to what elements are involved and the types of intramolecular bonds:

HCl, NaCl, CO2, Cu(ClO) 2, CaO, HF, Ca(OH) 2, HIO3, Sr(NO3) 2, Pb(NO3) 2, AgNO3, KBr, NaOH, N2O3, FeO, CH3COOH,


Analyze each pair name formula and come up with some rules
Analyze each pair (name = formula) and come up with some rules…

Hyroiodic Acid = HI

Nitrous Acid = HNO2

Nitric Acid = HNO3


Copper( rules…II) nitride = Cu(NO3)2

Sodium phosphate = Na2PO4

Gold(II) oxide = AuO


Sulphur rules…diflouride = SF2

Dinitrogen trioxide = N2O3


Balancing rules…

Chemical

Equations

“BCE”


Why? rules…


General guidelines
General Guidelines rules…

  • Balance any polyatomic ions first

  • Balance metals

  • Balance nonmetals

  • Balance “O” and “H” last

  • Recount both sides to make sure!!


Al o 2 al 2 o 3
Al + O rules…2 Al2O3


C 2 h 6 o 2 co 2 h 2 o
C rules…2H6 + O2 CO2 + H2O


Counting rules…

Significant

figures


Answers
Answers… rules…

100 = 1

0.001 = 1

0.010 = 2

10.04 = 4

1.0 x 102 = 2

197 = 3

0.0000200910 = 6

100.20 = 5

10.0 = 3

1090 = 3




Answers1
Answers… significant?

Adding and Subtracting…

10.00 + 2.0 = 12.0

36.98 – 0.0013= 36.98

General Rule?


Answers2
Answers… significant?

Multiplying and Dividing…

190 / 3 = 60

1403 / 7.0 = 2.0 x 102

0.09700 x 1.2 = 0.12

General Rule?


Mole significant?

Calculations


Answer
Answer… significant?

How many grams of NaCl are in 4.50 moles of NaCl?

# g NaCl = 4.50 mol x 58.5 g = 263 g NaCl

1 mol

What steps were used to answer this question?


Answer1
Answer… significant?

How many moles of NH4Br are in 15.87 g of NH4Br?

# mol NH4Br= 15.87g x 1 mol =0.162 mol NH4Br

97.9 g

What steps were used to answer this question?


General rules
General Rules… significant?


Basic significant?

Stoichiometry


Answers3
Answers… significant?

Given the following balanced equation, answer the questions following it:

9Na + 4ZnI2 8NaI + NaZn4

a.) If 2.50 moles of Na are reacted, how many moles of ZnI2 will be consumed?

# mol ZnI2 = 2.50 mol Na x 4 mol ZnI2 = 1.11 mol ZnI2

9 mol Na

b.) If you completely react 526.68 g of ZnI2, what mass of NaZn4 will be produced?

# g NaZn4 = 526.68g of ZnI2x 1 mol ZnI2 x 1 mol NaZn4 x 284.6g NaZn4 = 117.4g NaZn4

319.2 g ZnI2 4 mol ZnI2 1 mol NaZn4



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