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Kosi hitac

Kosi hitac. y. v o. y m. v oy. . v ox. x. D. x - smjer. y - smjer. v ox. v oy. v x = v ox. v y = v oy - gt. x = v ox t. y. v o. v o. 90 o - . . x. y. x. parabola. balistička krivulja. Primjer: Tijelo je izbačeno brzinom 100 m s -1 pod kutom 60 o

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Kosi hitac

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  1. Kosi hitac y vo ym voy  vox x D x-smjer y-smjer vox voy vx = vox vy = voy - gt x = voxt

  2. y vo vo 90o -   x y x parabola balistička krivulja

  3. Primjer: Tijelo je izbačeno brzinom 100 m s-1 pod kutom 60o prema horizontali. Kolika je njegova brzina 2 s nakon izbacivanja? Rješenje: vo= 100ms-1 = 60o vo vx= 50ms-1 voy t= 2 s 60o vy= v0y - gt v = ? vox = 86,6 m s-1 – 9,81 m s-22 s vy= 67 ms-1 vox= 50ms-1 v = 83,6 m s-1 voy= 86,6 ms-1

  4. Zadatak: Tijelo je izbačeno početnom brzinom 50 m s-1 pod kutom 30o prema horizontali. a) Koliko je tijelo udaljeno od mjesta izbačaja nakon 3 s? vo= 50ms-1 , t= 3 s vo voy 30o vox vox= 43,3 ms-1 voy= 25 ms-1 y= 30,9 m x=v0xt =43,3 ms-13 s x= 129,9 m r= 133,5 m

  5. b) Kolika mu je tada brzina? vx= 43,3 ms-1 vy= voy - gt = 25 m s-1 – 9,81 m s-23 s vy= - 4,4 ms-1 v = 43,3 ms-1 • c) Koliki mu je domet? , D = 220,7 m • d) Pod kojim bismo još kutom mogli izbaciti tijelo jednakom • početnom brzinom da ono ima jednaki domet? ,  = 60o  = 90o –  = 90o – 30o

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