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All approximation methods have assumed the Hamiltonian is constant in time

15. Time Dependent Approximation Methods. The Goal. All approximation methods have assumed the Hamiltonian is constant in time Now we will consider H = H ( t ) To make things simple, let the time dependence take place only over a time T Typically t = 0 to t = T

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All approximation methods have assumed the Hamiltonian is constant in time

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  1. 15. Time Dependent Approximation Methods The Goal • All approximation methods have assumedthe Hamiltonian is constant in time • Now we will consider H = H(t) • To make things simple, let the timedependence take place only over a time T • Typically t = 0 to t = T • Sometimes want to deal with H that alwaysvaries with time • Have it vary from t = – T/2 to t = T/2 • Take limit T   • Assume we have already found eigenstates of HIand HF: • Assume it starts in state |I • Evolve it forward to time T using Schrödinger • What is probability it ends in |F?

  2. 15A. The Sudden Approximation Short Time = No Change • Suppose H changes quickly from HI to HF, T small • We must solve Schrödinger: • Since T is small, use Taylor expansion:

  3. Comments On the Sudden Approximation • In general, though Fand Iare both eigenstates, they are eigenstates of different Hamiltonians When is this approximation valid? • The leading term we dropped was O(TH/) • H is of order the energies, so this is small if • Can show, only differences in energies matter, so really need • Probabilities are always pure numbers • If there are any dimensionful combinations in your answer, your answer is wrong • Answers should have a numerical answer  1

  4. Sample Problem A particle is initially in the ground state of a Harmonic oscillator potential with frequency(t), where(t) changes from 0 to 20 very quickly (T 0 << 1). What is the probability it remains in the ground state? • The probability is: • The initial state has wave function • The final state has same wave function,with 0 changed to 20: • The overlap is

  5. 15B. The Adiabatic Approximation Instantaneous Eigenstates • Suppose H changes slowly from HI to HF, T large • Ateach moment, find eigenstates of Hamiltonian • Eigenstates are always orthonormal, therefore • Take time derivative: • Imaginary part is undetermined: • The eigenvalue equation for |i(t) is ambiguous up to a phase • By multiplying |i(t) by a time-dependent phase, we can make it whatever we want • We can choose imaginary part to vanish too, so

  6. State Vector in Terms of Eigenstates • Let’s write |(t) in terms of our eigenstates • Substitute intoSchrödinger’s Equation: • Take inner product with one state n(t)|:

  7. Pulling Out the Large Phase • Because Hamiltonian is changing slowly, eigenstates are also changing slowly • Expect second term to be small • Solution to just first term is pretty easy • Let us define bnby • Substitute into differential equation:

  8. Integrating the Equation • The term with i = n is absent because • Integrate to get the total change in bn(t): Derivatives are small because H is slowly changing • But integration is over long time! • But it’s multiplied by a phase that is constantly changing • So it should be small, just need to prove it • For each value of i and n,define the phase angle  by • Note that • We therefore have:

  9. The Approximation • Integrateby parts: • If we assume that (T) is large, then derivatives are small • Every term inside {} should be small, so • Recall that

  10. Now We Tie It All Together • Recall what cn is: • Initial state assumed: • We want probability • It stays in the same state, of a different Hamiltonian • Normally, ground state  ground state, first excited  first excited, etc. • We explicitly assumed (T) is large • If we let E be typical energy splitting, then we are assuming • This is exact reverse criterion of sudden approximation

  11. Sample Problem A particle is initially in the ground state of a Harmonic oscillator potential with frequency(t), where(t) changes from 0 to 20 very slowly (T 0 << 1). What is the probability it remains in the ground state? • The probability is:

  12. Level Crossings • Sometimes, as the Hamiltonian evolves, eigenstates will have energies that approach each other • Adiabatic approximation applies only if we always have • Normally, the difference E will not vanish, because there will be mixing that causes the states to mix heavily as Hamiltonian changes • If there is mixing between the states, then we follow the general rule • Ground state  ground state, etc. • Suppose we have a symmetry operator T thatcommutes with the Hamiltonian at all times • Then eigenstates will be eigenstates of both T and H: • As time evolves, eigenvalue under T will stay the same • The lowest energy state with the initial eigenvaluewill become the lowest energy state with the same eigenvalue, etc. • You can have level crossings betweenstates with different values of .

  13. Sample Problem An electron in spin state |+ at t = –  is in a region with time-dependent magnetic field . What state will it be in at t = +  if: (a) eBx2 >> mb (b) Bx = 0 Bx = 0 Bx0 • The relevant Hamiltonian is: • Eigenvalue graph as a function of time: • Two spin states are mixed around t = 0 if Bx  0 • For characteristic time T ~ Bx/b • For part (a), the low energy state will remain the low energy states in adiabatic approximation: • Valid if • For part (b), the Hamiltonian always commutes with Sz • Therefore, Szeigenvalue will never change |– |+ |– |+

  14. 15C. Time-Dependent Perturbation Theory Setting Up the Problem • Consider a Hamiltonian with a small time-dependent part • Assume we know the eigenstates and eigenvalues of H0 • W(t) is assumed to be small • These states are a complete, orthonormal basis • We can write the state vector in terms of these states • Assume we start in state |I and want probability we end in state |F

  15. Schrödinger’s Equation • We now write out Schrödinger’s equation • Take inner product with n|

  16. Pulling Out the Large Phase • If W is small, we expect second term to be small • In absence of second term, solution to first is cn ~ exp(–iEnt/) • We therefore define: • Substitute in: • Define the frequency differenceand matrix element: • We therefore have:

  17. Integrating and Working on Answer • Integrate to time T: • Recall: • Therefore • Recall: • Define: • Then we have:

  18. Making a Series Expansion • Substitute this expression into itself repeatedly • We have a perturbative expansion for the transition

  19. Comments on Perturbative Expansion • We almost never interested in cases where F = I • Ignore first term • If we include only thesecondterm, then we get • Not hard to show that SFI is a unitary matrix • Closely related to U(T,0) being a unitary operator

  20. Sample Problem A hydrogen atom is in state |1,0,0 when it is subjected to a temporary electric field given by . What is the probability it transitions to state |n,l,m ? • Electric field comes from scalar potential and/orvector potential • We can use: • This adds perturbation • Matrixelement is • Normally, run time integral from 0 to T, but in this case, from – to +  • We have: • Non-zero only for l = 1, m = 0 • Vanishes if T = 0 (sudden approximation) • Vanishes if T =  (adiabatic approx.)

  21. 15D. Harmonic Perturbations Harmonic Perturbations • It is very common to have the perturbation looklike a sine or a cosine • These can be rewritten: • Define a harmonic perturbation as one of the form: • Assume   0 • We will use our perturbation expansion,but assume F  I, and only keep first order • We actually want to think of the perturbation as always present • Make t run from – T/2to +T/2; later take limit T   • Define WFIas • Then we have • Substitute in:

  22. Large Effects Near Resonance • Do the integrals: • In general, if W is small, expect these terms to be small • Unless we have a small denominator! • We will approximate two cases: • Where FI  (energy increasing) • Where FI  – (energy decreasing) • In each of these cases, we will only keeptrack of the large term, and ignore the other

  23. Energy Increasing Case – Large T limit • We want transition probability: • Consider limit T   • Look at function in {}’s: • As T  , it looks like a delta function • To find the coefficient A,integrate both sides over all  • Let Maple do the work,or use contour integration

  24. Some Reminders on Delta-Functions • General integralof a delta function: • This allows you torewrite delta functions • In particular, • We therefore have • Recall that: • So

  25. Transition Rates • Note that probability is proportional to T • The longer you wait, the more likely you are to have a transition • Define the rate  as the probability per unit time • This formula assumed EF > EI, we still need to do the other case • Then put the formulas together: • Note energy is not conserved • Not surprising for a non-constant Hamiltonian • Note the energy change is  • This energy is being added/subtracted from a classical background source • Later we’ll realize this is photon energy

  26. Reverse Transitions • Consider a case where EF > EI, and we consider F  I • Rate for forwards and backwards transitionsare the same! • Implies that in a thermal background, excited/ground states will eventually become equally populated • We’ll correct this false impression when we quantize EM fields

  27. What to Do With the Delta Functions • How should we handle the delta functions? • Naively, we would always get zero or infinity • The frequency might be changing with time • There might be many frequencies present • We’ll use this in a later chapter • There may be multiple final states that need to be added up, which can be converted to an integral • For example, final states are free particles • Deal with this in next section • If experiment is finite time, you can simply not take the limit T   • It ends up not quite a delta function

  28. Sample Problem A harmonic oscillator with mass m and angular frequency 0 is in the ground state |0 at t = 0, and is subjected to a perturbation . The angular frequency of the driving perturbation is gradually adjusted to increase, so  = t. To first order in perturbation theory, what state can it transition to, and what is the corresponding probability? • Since in the ground state,it can only go up in energy • Need to write perturbation in the form • We need the matrix element:

  29. Sample Problem (2) A harmonic oscillator with mass m and angular frequency 0 is in the ground state |0 at t = 0, and is subjected to a perturbation . The angular frequency of the driving perturbation is gradually adjusted to increase, so  = t. To first order in perturbation theory, what state can it transition to, and what is the corresponding probability? • This is the rate at any given time • We integrate this rate to get the total probability

  30. Sample Problem A hydrogen atom in its ground state is in a region of rapidly oscillating electric field in the z-direction, Ez= E0cos(t), where  is much larger than the binding energy of hydrogen. What is the rate at which it will dissociate the electron? • As usual, we have • Initial state is ground state of hydrogen: • EF will be large, so large that the finalelectron will effectively be a free electron • The electric potential is easily found • This lets us get the perturbation: • We now need the matrix element

  31. Sample Problem (2) A hydrogen atom in its ground state is in a region of rapidly oscillating electric field in the z-direction, Ez= E0cos(t), where  is much larger than the binding energy of hydrogen. What is the rate at which it will dissociate the electron?

  32. Sample Problem (3) A hydrogen atom in its ground state is in a region of rapidly oscillating electric field in the z-direction, Ez= E0cos(t), where  is much larger than the binding energy of hydrogen. What is the rate at which it will dissociate the electron? • After a lotof work: • The energy of the final states is • Decay rate to a particular k is: • The states |k are continuum states • We can go into any |k to dissociate

  33. 15E. EM Waves and the Dipole Approximation The Perturbation • Consider the effects of an external electromagnetic field on an atom • We start with the Hamiltonian: • The potential Vacontains all the internal interactions of the atom with itself • The unperturbed Hamiltonian is just: • Assume we know the eigenstates |a • Assume the external fields are small • Only keep first order in A • The perturbation will be: • We implicitly assumed PA = AP • Works if A = 0 • We’ll justify this assumption shortly

  34. The Waves • We now need to make an electromagnetic wave • Multiple ways to do this, but oneway (Coulomb gauge) is to use: • The polarization vector  is a normal vector perpendicular to k: • Note that this satisfies A = 0 • Moves at speed c: • The electric andmagneticfields are: • So we have: • Compare with: • So we have:

  35. The Dipole Approximation • We will need matrix elements • Atomic states have size ~ a0 • We will typically be working with waves with energy of order the binding energy of the atom • We therefore will have • Therefore, kRj << 1 • The relative size of the secondterm compared to the first is: • We make the electric dipole approximation:

  36. Working With the Dipole Approximation • There is a better way to work out this matrix element. Consider: • It follows that: • Our rate is therefore:

  37. Rewrite in Terms of Intensity • You can’t measure the vector potential A, just the fields E and B • Most commonly, you measure the intensity , the power per unit area • Computed in E&M as the time-averaged magnitude of the Poynting Vector: • Time average and expand out the triple cross products: • Use that  is normalized and orthogonal to k • The intensity is therefore • And we therefore have

  38. Putting it All Together • Define the dipole matrix element • Speed of light,from E&M: • Recall • Substitute in: • Fine structure constant: • Delta function assures that = FI, so this simplifies to:

  39. Dealing With the Dirac Delta Function • How do we deal with the delta function? • Often, incident light has a range of frequencies: • Logically, should be called d/d, but it isn’t • Other measures ofintensity are related: • Replace  byan integral: • So we have:

  40. Averaging Over Polarization, And Direction • Formula assumes we know the polarization  • If incident light is unpolarized, need to averagethe two polarizations perpendicular to k • For example, let’s assume rFI is real • Let  be angle between k and rFI • One polarization can be chosen in the plane of k and rFI • The other is perpendicular to both k and rFI • The rate, averaged overpolarizations will be: • If direction of light (or orientationof atom) is random, we can alsoaverage over angles

  41. Comments on Electric Dipole Rate • If you know the polarization, you don’t need all components of rFI • Just calculate the component you need: Only certain states have non-zero matrix elements • Non-zero only if • Because operator R is parity -1, initial and final states must have opposite parity • This is automatically assured by l = 1 for Hydrogen, but not for other atoms • If l  1, then electric dipole can’t cause transition • But higher order interactions can

  42. Sample Problem An electron is trapped in the ground state of a cubical box of size a3, with a corner at the origin. It is then bathed in light moving in the z-direction,polarized in the x-direction, and having intensity function (). In the dipole approximation, (a) which states can the electron transition into, (b) what are the corresponding frequencies , and (c) what are the transition rates • We first need the eigenstatesand eigenergies of the electronin the box: • Polarization is • We need matrix element • Only states possible are|n11 with n even

  43. Sample Problem (2) (b) what are the corresponding frequencies , and (c) what are the transition rates • The frequencies are (n is even): • The rate is:

  44. 15F. Beyond the Dipole Approximation Higher Order Terms • Recall: • We dropped second term and kRj because they were smaller by factors of ka0 ~  • So, keep them toone more order • First term leads toelectric dipole term • For the second term,use this identity: • Rewrite as • Newterms:

  45. Electric Quadrupole and Magnetic Dipole • Last term: • Magnetic dipole term: • We’ll set this aside and let you work on it with homework • The remaining term is the electric quadrupole term:

  46. Simplifying the Electric Quadrupole Term • As before, we can use a clever commutator to simplify: • So we have:

  47. Simplifying the Electric Quadrupole Term (2) • Let H0 act to theleft or to the right,as before • Now get the rate: • As usual, convert to intensity

  48. Putting It Together • Use fine structure constant • As before,  = FI because of the delta function • Integrate over  • Final answer:

  49. Comments on E2 and M1 transition • Electric quadrupole term2 tends to be down by factor of (ka0)2 ~ 2 compared to electric dipole • Same can be proven about the magnetic dipole contribution The electric quadrupole term can be shown to be a rank-2 spherical tensor • Means that |l| = 0, 1 or 2 Both electric quadrupole and magnetic dipole commute with parity • Connect only same parity states • Unlike electric dipole, which reverses parity • Means no interference with electric dipole Magnetic dipole operator commutes with H0 • Only connects states that are split by smaller effects • Spin orbit • Hyperfine • External B-field

  50. Sample Problem An electron is trapped in the ground state of a cubical box of size a3, with a corner at the origin. It is then bathed in light moving in the z-direction,polarized in the x-direction, and having intensity function (). In the electric quadrupole approximation, (a) which states can the electron transition into, (b) what are the corresponding frequencies , and (c) what are the transition rates • We first need the eigenstatesand eigenergies of the electronin the box: • Polarization is • We need matrix element • Only states possible are|n1p with n,p even

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