- 119 Views
- Uploaded on
- Presentation posted in: General

Momentum

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Momentum

- What is the equation the links momentum with mass and velocity? …momentum = mass x velocity ……..(1mark)
- A car of mass 1000kg is travelling at 15m/s, what is its momentum? ……15000 N s (kg.m/s) …………(1 mark)
- A 0.5kg trolley A is pushed at a velocity of 1.2m/s into a stationary trolley B of mass 1.5kg. The two trolleys stick to each other after the impact. What is the momentum of trolley A before the collision. What is the velocity of the two trolleys after the collision?
- 0.6 N s (kg.m/s)
- 0.3 m/s…(3 marks)
- 4) A car is travelling at 10m/s, it hits and stays in contact with another car of the same mass. What is the resultant speed of the two cars together? ……
- the momentum has to be conserved. If the mass is doubled the velocity will be halved. 5m/s…(2 marks)
- 5) Trolley A of mass 2kg is travelling at 0.3m/s. Trolley B of mass 2.5kg is travelling in the opposite direction at 0.2m/s. The two trolleys collide and stick together. At what velocity do the trolleys travel after the collision? …2X0.3 = 0.6 (left) 2.5X0.2 = 0.5 (right) resultant 0.1 (left) 4.5 x ? = 0.1 velocity = 0.02m/s …………………………………………………………………………… (3 marks)

6) What equation links change in momentum, time and force? … force = change in momentum / time (1 mark)

7) A bullet of mass 0.004kg moving at a speed of 90m/s is stopped by a little bullet-proof vest in 0.0003s. Calculate the impact force.

0.004 x 90 = 0.36 0.36/0.0003 1200N (2 marks)

8) At turn 8 of the Spanish grand prix Heikki Kovalainen went off the track at 100miles per hour (45m/s). The car hit the tyre wall and came to a stop in 0.08s. A F1 car has a mass of 604kg. Calculate the force on the car.

45 x 604 = 27180 27180/0.08 339750 (2 marks)

9) A car of mass 900kg is travelling at 13m/s when it hits another, stationary, car of mass 750kg. Both cars then collide into a wall and come to a stop with an acceleration of -0.5m/s2. How long did it take the cars to com to a complete stop and what was the force on the cars during this time?

A – 900 x 13 = 11700 kg m/s

f = ma = 1650 x 0.5 = 825N

AB - time = change in momentum/force = 11700/825 = 14.2s

(4 marks)