geometry a bowerpoint presentation
Download
Skip this Video
Download Presentation
Trigonometric Ratios – Solving For Angles

Loading in 2 Seconds...

play fullscreen
1 / 15

Trigonometric Ratios – Solving For Angles - PowerPoint PPT Presentation


  • 192 Views
  • Uploaded on

Geometry A BowerPoint Presentation. Trigonometric Ratios – Solving For Angles. Calculator Practice. Try these on your calculator to make sure you are getting correct answers: Sin (0.7660444) = 50° Cos (0.4694716) = 62° Tan (3.73205081) = 75°

loader
I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
capcha
Download Presentation

PowerPoint Slideshow about ' Trigonometric Ratios – Solving For Angles' - hye


An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
calculator practice
Calculator Practice
  • Try these on your calculator to make sure you are getting correct answers:
    • Sin (0.7660444) = 50°
    • Cos (0.4694716) = 62°
    • Tan (3.73205081) = 75°
  • You may need to use a “2nd” function on your calculator to use sin x , cos x , tan x. Look above the buttons for sin x , cos x , and tan x.

-1

-1

-1

-1

-1

-1

solving for angles of right s
Solving for angles of right ∆s
  • If you know the lengths of any two sides of a right triangle, that is enough information to find the acute angles.

18

40

step 1 choose an acute
Step 1 – Choose an acute ∡
  • We will solve for the angle that is x°

18

40

step 2 label the sides
Step 2 – Label the sides
  • The hypotenuse is across from the right angle
  • Label the legs as opposite and adjacent (positions relative to the angle with x°)

18

40

step 2 label the sides1
Step 2 – Label the sides
  • The hypotenuse is across from the right angle
  • Label the legs as opposite and adjacent (positions relative to the angle with x°)

hyp

18

opp

40

adj

step 3 select ratio
Step 3 – Select ratio
  • Look at the two sides for which you know the lengths
  • We know opp = 18 and adj = 40

hyp

18

opp

40

adj

step 3 select ratio1
Step 3 – Select ratio
  • Look at the two sides for which you know the lengths
  • We know opp = 18 and adj = 40
  • Which ratio has opp and adj?

hyp

18

opp

40

adj

step 3 select ratio2
Step 3 – Select ratio
  • Look at the two sides for which you know the lengths
  • We know opp = 18 and adj = 40
  • Which ratio has opp and adj? SOH – CAH – TOA

TANGENT

hyp

18

opp

40

adj

step 4 fill in and solve
Step 4 – Fill in and solve

opp

18

40

adj

tan x ° = = = 0.4500

hyp

18

opp

40

adj

step 4 fill in and solve1
Step 4 – Fill in and solve

opp

18

40

adj

tan x ° = = = 0.4500

tan x ° = 0.4500 We will use the tan x buttonon a calculator to answer the question “What angle has a tangent of 0.4500?”

-1

hyp

18

opp

40

adj

step 4 fill in and solve2
Step 4 – Fill in and solve

tan x ° = 0.4500 can be rewritten as

tan (0.4500) = x (You don’t have to rewrite it this way as long as you know what to do on your calculator)

-1

hyp

18

opp

40

adj

step 4 fill in and solve3
Step 4 – Fill in and solve

tan x ° = 0.4500 can be rewritten as

tan (0.4500) = x

-1

x = 24.2

(rounded to nearest tenth)

hyp

18

opp

40

adj

solving for angles of right
Solving for angles of right ∆
  • Step 1
    • Choose an acute angle
  • Step 2
    • Label sides of the triangle (hyp, opp, adj)
  • Step 3
    • Select ratio (sin, cos, tan)
  • Step 4
    • Fill in and solve
ad