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Modeling Line Drop Compensation, Reactive Current Compensation, Cross-Current Compensation. Dmitry Kosterev BPA November 2013. Basics. XT = 12 to 20%. Line Drop Compensation. Generator Terminal Voltage. 01. Reactive Current Compensation.

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modeling line drop compensation reactive current compensation cross current compensation

ModelingLine Drop Compensation, Reactive Current Compensation, Cross-Current Compensation

Dmitry Kosterev

BPA

November 2013

basics
Basics

XT = 12 to 20%

Line Drop Compensation

Generator Terminal Voltage

01

Reactive Current Compensation

gentpj 1 “UNIT1” 13.8 “01”: … “xcomp” 0.05

gentpj 2 “UNIT2” 13.8 “01”: … “xcomp” 0.00

gentpj 3 “UNIT3” 13.8 “01”: … “xcomp” – 0.05

basics1
Basics

POI Voltage

Line Drop Compensation

Generator Terminal Voltage

Reactive Current Compensation

Generator Reactive Power

slide4

General Rule

01

02

RCC = – 5%

Model:

gentpj 1 “UNIT1” 13.8 “01”: … “xcomp” – 0.05

gentpj 1 “UNIT1” 13.8 “02”: … “xcomp” – 0.05

slide5

Modeling

In General Electric PSLF:

“xcomp” is negative for Reactive Current Compensation

In Siemens PTI PSS®E:

“xcomp” is positive for Reactive Current Compensation

Many cases when the data is converted incorrectly between the programs:

E.g.Rock Island,Ryan,Magcorp

slide6

General Rule

Positive “xcomp” will result in sister units becoming unstable (one goes full boost, one goes full buck) if they have different parameters or initial unit loading

Voltage

Field Voltage Unit 1, Field Voltage Unit 2

Reactive Power Unit 1, Reactive Power Unit 2

slide7

Rule Breakers – US ACE and BPA

LDC = + 5%

01

02

Cross-Current Compensation

slide8

Modeling

  • Present practice is to use the positive “xcomp” to represent Line Drop Compensation
  • Cross-compensation is not modeled
  • John Day, The Dalles and Willamette Valley plants
  • Models can have “xcomp” positive as long as two sister units have identical models and data, and have the same MW and MVAR output
  • State estimator models have units dispatched at different MW levels
  • Need to make sure models are stable
slide9

Modeling

XCOMP (Existing practice):

gentpj 1 “UNIT1” 13.8 “01”: … “xcomp” +0.045

gentpj 1 “UNIT1” 13.8 “02”: … “xcomp” +0.045

CCOMP:

gentpj 1 “UNIT1” 13.8 “01”: … “xcomp” 0.0

gentpj 1 “UNIT1” 13.8 “02”: … “xcomp” 0.0

ccomp 1 “UNIT1” 13.8 “01”: “rc” 0.0 “xc” –0.05 “rt” 0.0 “xt” 0.045

XCOMP_CCOMP:

gentpj 1 “UNIT1” 13.8 “01”: … “xcomp” 0.045

gentpj 1 “UNIT1” 13.8 “02”: … “xcomp” 0.045

ccomp 1 “UNIT1” 13.8 “01”: “rc” 0.0 “xc” –0.05 “rt” 0.0 “xt” 0.0

slide10

Model Testing

01_02

_02

01_

01

01

01

02

02

02

slide11

Model Testing

LDC Setting is 4.5%

Voltage dip is simulated, effective LDC is measured

slide12

Recommendations

  • Use CCOMP model to represent cross-current compensation when used
  • Make changes to CCOMP and XCOMP models to work together
    • If “xt” in “ccomp” is zero, continue using “xcomp” parameter from “gentpj” model
    • If “xt” in “ccomp” is non-zero, set “xcomp” parameter to zero in “gentpj” model
  • John Day has +0.045 LDC and cross-current compensatio
  • Make sure that the following works
    • Set “xc” to –0.05 and “xt” to 0.0 in “ccomp” model
    • Set “xcomp” to 0.045 in “gentpj” model
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