The mathematics of fm radio
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The Mathematics of FM Radio. 6 . 1 . 00. Randy Franks. Jon Nakashima. Matt Snider. Radio Basics. AM = Amplitude Modulation. FM = Frequency Modulation. FM waves require line-of-sight between transmitter and receiver.

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The Mathematics of FM Radio

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The mathematics of fm radio

The Mathematics of FM Radio

6 . 1 . 00

Randy Franks

Jon Nakashima

Matt Snider


Radio basics

Radio Basics

AM = Amplitude Modulation

FM = Frequency Modulation

FM waves require line-of-sight between transmitter and receiver.

AM waves use line-of-sight, but can also reflect off the ionosphere and then to a receiver.


Basic schematic symbols

Basic Schematic Symbols

battery

transistor

inductor

resistor

capacitor

An arrow across a component indicates its level is variable.

Schematic of a basic transmitter


The mathematics of fm radio

Our FM Receiver :

a Schematic


Capacitors

Capacitors

- like a battery

- stores charge

- when the device needs extra power, say for a particularly loud sound, the capacitor discharges

“dielectric”- a material placed between the plates of the capacitor to increase capacitance

“electrolytic” – type of capacitor which has strict polarity (charge may only flow in one direction through this type of capacitor)


Internal capacitor design

Internal Capacitor Design

A parallel-plate

capacitor

A variable capacitor

A cylindrical capacitor

(really, it’s just a stack of parallel plates)

(cross-section from above)


Calculating the capacitance

Calculating the Capacitance

Basic Strategy: use equations for q and V separately , solve for the situation, divide and simplify results

 electrostatic charge

voltage 


Parallel plate capacitor

Parallel Plate Capacitor

d = separation of plates

A = area of Gaussian surface

Again, E and ds are in the same direction. Also the integral of ds from one plate to the other is equal to the total separation.

E and dA are parallel, and dA is a constant, in this case. So….

So….


Cylindrical capacitor

Cylindrical Capacitor

(cross section)

a = inside radius

b = outside radius

r = radius of Gaussian surface

From the last derivation:

A = area of Gaussian surface, which is now cylindrical. A = 2πrl, So….

Solving the above for E will prove useful in the determination of V, So….


Cylindrical capacitor cont

Cylindrical Capacitor (cont.)

First, replace ds with dr, since the Gaussian surface is circular. Second, substitute for E (using result of last page).

a = inside radius

b = outside radius

r = radius of Gaussian surface

Third, change the integral limits to a and b (from the inside radius to the outside radius. After all that….

Finally, it’s time to divide the two results.

A lot of Algebra later:

Pull out constants, and….

Evaluating the integral leaves:


And that s it

And that’s it!

Well, almost….

Matt will now perform the ritual dance necessary to achieve decent radio reception on this campus.


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