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Equation of Straight LinePowerPoint Presentation

Equation of Straight Line

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Equation of Straight Line

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Equation of a straight line (gradient-intercept form):

y = mx + c where m is the gradient and c is the y-intercept.

Equation of a straight line (given gradient and 1 point):

Find the equation of the straight line joining

(2, 4) and (–2, 3)(–2, – 4) and (1, –7)

Find the equation of the lines, given the

gradient and the coordinate of a point lying

on the line.

(a) m = 3, (1, 1)(b) m = 0.5, (5, 7)

- What is the equation of the line which has gradient 2 and which passes through the origin?

- Find the equation of the straight line that is parallel to and bisects the line segment joining the points (3, 1) and
(1, –5).

Find the values of k if the line

is parallel to

Given the line, find

- its gradient;
- the coordinates of the point at which it cuts the x-axis.

Double-intercept form

General form

Gradient-intercept form

*Given gradient and 1 point

3 points are collinear if gradient AB = gradient BC