- 138 Views
- Uploaded on
- Presentation posted in: General

Concentration Units

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.

- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Concentration Units

Percent by mass, mole fraction,

molarity, and molality

PERCENT BY MASS =

MASS OF SOLUTE

X 100%

MASS OF SOLUTION

A sample of 0.892g of potassium chloride is dissolved in 54.6g of water.

What is percent by mass of KCl in the solution?

0.892g

Percent by mass of KCl =

X 100%

0.892g + 54.6g

= 1.61%

Concentration Units

Percent by mass, mole fraction,

molarity, and molality

MOLE FRACTION OF COMPONENT A = XA =

Moles of A

Σ all moles in solution

Your solution contains 5 moles of KCl and 15 moles of water.

What is the mole fraction of KCl?

5 moles KCl

XKCl =

= 0.25

5 moles KCl + 15 moles H2O

What is the mass percent of KCl?

74.55 g

5 molKCl x

Mass percent of KCl =

1 molKCl

= 58%

74.55 g

18.02 g

15 mol H2O x

5 molKCl x

+

1 molKCl

1 mol H2O

Concentration Units

Percent by mass, mole fraction,

molarity, and molality

Moles of solute

Moles of solute

MOLALITY = m =

MOLARITY = M =

Kg of solvent

Liters of solution

Calculate the molality of a sulfuric acid solution containing 24.4g of sulfuric acid in

198g of water. The molar mass of sulfuric acid is 98.09 g/mol.

1 mol H2SO4

24.4 g H2SO4 x

mH2SO4 =

98.09 g

= 1.26m = 1.26 “molal”

0.198 kg H2O

What is the molarity of the solution? (d = 1.84 g/mL)

1 mL

= 120.87 mL

Volume of solution =

(24.4g + 198g)

1.84g

0.2487 mol H2SO4

Molarity = M =

= 2.06M = 2.06 “molar”

0.12087L solution