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Inflation

Inflation. November 8, 2010.

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Inflation

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  1. Inflation November 8, 2010

  2. Inflation can be defined as the rate of decline in the purchasing power of money.Purchasing power might be defined as: a) kg of wheat you can get for a dollar b) floating-point operations you can perform for a dollar c) hours of human labour you can purchase for a dollar

  3. Measuring Inflation The Consumer Price Index

  4. Measuring Inflation The Consumer Price Index 2. The Industry Selling Price Index

  5. Measuring Inflation The Consumer Price Index 2. The Industry Selling Price Index 3. The Implicit Price Index

  6. Hyperinflation In some countries, the purchasing power of money has declined rapidly and catastrophically – for example, the Weimar Republic in the 1920’s.

  7. Hyperinflation …and in Yugoslavia in the 1990’s…

  8. Hyperinflation …and in Zimbabwe right now…

  9. If there is consistent inflation at a given rate, your wages go up by the same percentage as your bills. So there should be no net effect on the economy. Why Does it Matter?

  10. One cause is the government printing money. But inflation can also occur in a gold-backed currency – for example, when Pizarro conquered Peru Causes of Inflation

  11. There has been… Why is there never Deflation? In the US, 1873-1896 (after the Civil War), and again in the Great Depression In the UK, 1919 (after WWI). In Japan, 1996--2006.

  12. a) Less than 3%: ignore it Dealing with Inflation b) more than 3%: plan for it

  13. Establish a reference point in time (e.g., Nov 08, 2010) • At the reference point, 1 constant dollar = 1 actual dollar • At any other time, an actual dollar is a loonie, whereas a • constant dollar is that sum of money needed to buy the • goods that a loonie would have bought on November 08, • 2010. Actual Dollars and Constant Dollars

  14. Confusing Terminology Uninflated Inflated Real cash flow Real dollars Today’s dollars Constant dollars Now dollars Constant worth dollars Nominal cash flow Actual dollars Current dollars Then-current dollars Then dollars Actual cash flow

  15. Two Strategies: • Convert all cash flows to constant dollars • (not recommended) • 2. Perform calculations using actual dollars • (recommended, especially for after-tax • analysis)

  16. Example: An asset can be purchased for $120,000. It costs $12,000/year to operate, and generates a revenue of $40,000/year (both these estimates assume no inflation). If the real MARR is 15% and the inflation rate is 8%, do a pre-tax analysis to see if it should be purchased.

  17. Real-dollar Analysis: PW = -120,000 +28,000(P/A,15,6) = -120,000 + 28,000(3.7844) = -14,037

  18. Analysing with Actual Dollars To perform calculations with actual dollars, we need to adjust the MARR. The adjusted, or inflated, or nominal MARR, MARR*, can be calculated from the real MARR via MARR* = (1+MARR)(1+f) -1 where f is the rate of inflation.

  19. MARR*= (1+MARR)(1+f) -1 The adjusted, or inflated, or nominal MARR Real MARR Which is bigger, nominal MARR or real MARR?

  20. We will also refer to MARR* as if

  21. if= (1+i)(1+f) – 1 = (1.15)(1.08)-1 = 0.242 -14,037

  22. This seems like a lot of extra work for nothing. But we need it if we’re going to do after-tax analysis. Consider the same problem, and suppose the asset is in Class 8 (declining balance depreciation at 20%) and the tax rate is 40%. So present worth, after tax, is -37,658

  23. Based on the cost of capital, your company’s MARR is 10% You expect 5% inflation in the future. You calculate the IRR of a proposed project, based on actual cash flows. What is the minimum value of IRR needed for you to accept the project?

  24. Buying Versus Leasing A piece of heavy equipment can be bought for $100,000 It will last for 10 years, and falls into Class 8 (d=0.2). Alternatively, the equipment can be leased for $20,000 a year, with an option to buy for $5,000 at the end of the eighth year. Assuming we would buy it at the end of the eighth year, and that we can deduct the lease cost from pre-tax income, should we lease or buy? (The tax rate is 40% and the after-tax cost of capital is 10%.)

  25. Buy Now

  26. Lease

  27. Now suppose we expect 10% inflation over the next ten years. Case 1: The lease costs are fixed by contract; do we buy or lease? Case 2: The lease costs rise at the same rate as inflation; do we buy or lease? In either case the inflated MARR is: if= (1+i)(1+f) – 1 = (1.10)(1.10)-1 = 0.21

  28. Buying: Both cases

  29. Case 1: The lease costs are fixed by contract

  30. Case 2: The lease costs rise with inflation

  31. Leasing Versus Buying. A company is considering whether to rent or to buy a Plebney machine. It costs $100,000 to buy, and $40,000/year to rent. The company will need the machine for another three years, after which it will have a salvage value of $20,000. The machine depreciates at 30% per year. The company’s pre-tax MARR is 10%; lease charges are paid on Dec 31.

  32. Case 1: No Tax, No Inflation Buy: PW = -100,000 + 20,000(P/F,0.1,3) = -100,000 + 20,000(0.7513) = -84,974 Lease: PW = -40,000(P/A,0.1,3) = -40,000(2.487) = -99,480

  33. Case 2: 50% Tax, No Inflation After tax MARR = 0.1 × 0.5 = 0.05 Buy: PW = -100,000×CCTF* + 20,000(P/F,0.05,3)×CCTF CCTF = 1 – td/(i+d) = 1 – 0.5×0.3/0.35 = 0.57 CCTF* = 0.58 So PW = -58,000 + 11,300(0.86) = -$48,282 Lease: PW = -40,000(P/A,0.05,3)(1-0.5) = -40,000(2.72)(0.5) = --$54,400

  34. Case 3: 50% Tax, 15% Inflation After tax MARR = 0.1 × 0.5 = 0.05 Inflated after-tax MARR* = (1+MARR)(1+f) -1 = 1.05×1.15-1 = 0.21 Assume salvage price does not inflate Buy: PW = -100,000×CCTF* + 20,000(P/F,0.21,3)×CCTF CCTF = 1 – td/(i+d) = 1 – 0.5×0.3/0.51 = 0.706 CCTF* = 0.73 So PW = -73,000 + 14,012(0.56) = -$65,153 If salvage price rises with inflation, then PW = -100,000×CCTF* + 20,000(P/F,0.05,3)×CCTF = -$60,857

  35. Case 3: 50% Tax, 15% Inflation Lease Costs fixed by Contract (actual dollar costs constant): PW = -40,000(P/A,0.21,3)(1-0.5) = -40,000(2.07)(0.5) = -$41,400 Lease Costs rise with inflation (actual dollar cost increases, real dollar cost constant): PW = -40,000(P/A,0.05,3)(1-0.5) = -40,000(2.72)(0.5) = -$54,400

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