1 / 8

Factoring Trinomials

Factoring Trinomials. Mrs. Unger’s Method… The Box Method + Part of the Master Product Method. Ex1: k 2 + 9k + 20. +4. k. 1.) Draw box. k 2. 4k. k. 20. +5. 5k. 2.) Write 1 st term in 1 st box, and 3 rd term in 4 th box. 3 .) Find Master Product. (1)(20) = 20. 1, 20

haven
Download Presentation

Factoring Trinomials

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Factoring Trinomials Mrs. Unger’s Method… The Box Method + Part of the Master Product Method

  2. Ex1: k2 + 9k + 20 +4 k 1.) Draw box k2 4k k 20 +5 5k 2.) Write 1st term in 1st box, and 3rd term in 4th box. 3.) Find Master Product (1)(20) = 20 1, 20 2, 10 4, 5 4.) List factors of MP to find two whose sum equals “b”. 5.) Put factors in remaining boxes with variable. **The sign stays with the middle terms.** 6.) Factor out GCF in each row. 7.) Factor out GCF in each column. 8.) Write your answer! (k + 5)(k +4)

  3. Ex2: 2x2 – 11x + 12 -4 x 1.) Draw box 2x2 -8x 2x 12 -3 -3x 2.) Write 1st term in 1st box, and 3rd term in 4th box. 3.) Find Master Product (2)(12) = 24 -1, -24 -2, -12 -3, -8 -4, -6 4.) List factors of MP to find two whose sum equals “b”. 5.) Put factors in remaining boxes with variable. **The sign stays with the middle terms.** 6.) Factor out GCF in each row. 7.) Factor out GCF in each column. 8.) Write your answer! (2x – 3)(x – 4)

  4. Ex3: –10 + 24z – 8z2 Before we can do anything, we have to rearrange. –8z2 + 24z – 10 GCF = –2 And then we have to take out the GCF. **Quadratic term MUST be positive.** –2(4z2 – 12z + 5) (4)(5) = 20 -1, -20 -2, -10 -4, -5 -1 2z 4z2 -2z 2z (2z – 5)(2z – 1) –2 5 -5 -10z But don’t forget that -2 we took out earlier!

  5. Ex4: 15x2 + 13xy + 2y2 But what happens when we have TWO variables??? It’s no big deal. It’s the same method. GCF = 1Well that doesn’t help! Check for the GCF, first. Ok, here we go… (15)(2) = 30 1, 30 2, 15 3, 10 5, 6 +y 5x 15x2 3xy 3x (3x + 2y)(5x + y) 2y2 +2y 10xy

  6. Ex5: a2 – 2a – 35 Check for the GCF, first. GCF = 1Well that doesn’t help! (1)(-35) = -35 1, -35 -1, 35 5, -7 -5, 7 +5 a a2 5a a (a – 7)(a + 5) -35 -7 -7a

  7. Ex6: 5 + 7x – 6x2 Before we can do anything, we have to rearrange. –6x2+ 7x + 5 And then we have to take out the GCF. (6)(-5) = -30 We have to take out a –1 to make the quadratic term positive. 1, -30 -1, 30 2, -15 -2, 15 3, -10 -3, 10 5, -6 -5, 6 –1(6x2 – 7x – 5) – 5 3x 6x2 – 10x 2x –1(3x – 5)(2x + 1) –5 +1 3x Pretty easy, right???

  8. Happy Factoring!!!

More Related