slide1
Download
Skip this Video
Download Presentation
Lecture 30

Loading in 2 Seconds...

play fullscreen
1 / 9

Lecture 30 - PowerPoint PPT Presentation


  • 143 Views
  • Uploaded on

Lecture 30. Motional emf is a special case of Faraday’s Law. General form of Faraday’s Law:. The path is the Faradian loop. Check: Moving rod along two || railing setup gives: which can be derived based on Faraday’s Law. From motional emf:.

loader
I am the owner, or an agent authorized to act on behalf of the owner, of the copyrighted work described.
capcha
Download Presentation

PowerPoint Slideshow about ' Lecture 30' - hall


An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -
Presentation Transcript
slide1

Lecture 30

Motional emf is a special case of Faraday’s Law

General form of Faraday’s Law:

The path is the Faradian loop.

slide2

Check: Moving rod along two || railing setup gives:

which can be derived based on Faraday’s Law

From motional emf:

slide3

We see (2) and (2’) agree with (3) and (3’). Our motional emf is a spherical case of Faraday’s law.

One can show in the case of current loop from both consideration one finds:

slide7

Example Problem:

Determinethe direction of the magnetic field in the coil with the battery attached.

Determine the direction of the magnetic field in the coil with the resistor attached

Determine The direction of the induced current in the resistor

Hint:

slide8

Example Problem:

If I1 is decreasing, find direction of emfind in the loop

Choices

1 – CW

2 - CCW

slide9

Example Problem

Determine the direction of the force on the segment AB as B is decreasing.

Hint: The force on ab is given by:

First determine the direction of Bin(should it be into or out)

The correct response is to keep flux within the loop constant

ad