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Service Deployment in Large Scale Network

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Service Deployment in Large Scale Network

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Service Deployment in Large Scale Network

Yung-Mu Chen, Wei-Jr Yin, Wei-Hua Chen, and Yu-An Chen

U90.armor@netlab.cse.yzu.edu.tw

Internet System Measurement and Analysis Team

- Introduction
- Algorithm
- Experiment environment
- Simulation Plan
- Problem
- Future work

- Finding an optimal deployment in a large scale computer network is a NP-Hard Problem.
- Using heuristic algorithm can find a feasible solution.

How to Assign the task graph

?

Task

Internet

Partition

Group map

Fail

CSP

Fail

Success

0

Dst

2

1

Src

Topology

2

1

3

S

5

4

6

7

11

8

9

10

12

D

13

14

Y

X

Z

Task Graph

- 先將具有source node或 destination node 的 group做相對應的 mapping
- 分別以 task graph 和 topology graph 兩圖具有source node 的 group 當作起點做 BFS，依照拜訪的順序，分別做 mapping

BFS

2(dst)

0

X(src)

Y

BFS

1(src)

Z(dst)

Topology group

Task group

Built Level

build level : we will build level in the every group

there is a source of group to be needed.

4

Src.

3

3

0

1

1

2

4

3

3

2

2

4

1

3

0

Src.

In the topology use the source

to build level by BFS.

In the task graph use the source

to build level by BFS.

Topology

Task

Merge level :

by a rule to make the topology and the task graph’s level

to be the same

y

Topology graph

definition :

k

Task graph

Ω

The graph group total numbers

Φ

The graph node total numbers

¥

The graph total level number of group

Gn

the group of graph , n = 0 ~ Ω- 1

Nn

n = 0 ~Φ - 1

the node of graph ,

Ln

n = 0 ~ ¥ - 1

the level of graph group ,

Φn

the node total numbers of the level

rule:

By group mapping we will allocate task group α to topology groupβ

If

¥y >

¥k

Gyβ

¥y =

¥k

Merge

Until

If

¥k >

¥y

Gkα

¥y =

¥k

Merge

Until

Gx

Merge

Ln

Φn

Choose the which have the min

L0 has been choose

If

L1

L0

Add nodes of into

Gx

Adjust level of

L¥ - 1 has been choose

If

L¥ - 1

L¥ - 2

Add nodes of into

Gx

Adjust level of

else

Li

Lj

Φn

Choose the near which have the min

Li

Lj

Add nodes of into

Gx

Adjust level of

Example:

Topology will be merged

Level 0 :

Level 1 :

Level 2 :

Level 0 :

Level 1 :

Level 2 :

Level 3 :

Level 4 :

Level 0 :

Level 1 :

Level 2 :

Level 3 :

merge level 0 and level 1

merge level 0 and level 1

done

CSP

definition :

Cy

The cpu capacity of the topology node

Ck

The cpu consumption of the task node

Dy

The disk capacity of the topology node

Dk

The disk consumption of the task node

node allocating : we will allocate the task node to topology node by a rule.

rule:

After mergelevel we will allocate nodes of task to nodes of topology

with the same level in and

Gkx

Gyx

Li

Gkx

Gyx

for all of and

Lki

Lyi

Ni

for all of and

Cy >

Ck and

Dy >

Dk

If

Allocate

else

Nyi

Check next

Nyi

Li

If all of doesn’t match

Multiply allocate

Example :

task

topology

Level 0 :

Level 1 :

Level 2 :

path allocating : after node allocating we will allocate task path on the

topology by Dijkstra algorithm with checking bandwidth.

- Pentium !!! 1GHz ,RAM 512 MB
- Platform: Debian 3.0
- C language
- Implement a timer
- Total time:10800 sec
- Time unit: 0.000001 sec

S

2

0

1

3

4

6

7

5

11

10

8

9

12

13

15

14

D

Node Edge metis constraint Group

0

1

2

3

GroupID CPU Disk [nodeID delay BW]

15

Node Edge

NodeID1 NodeID2 Delay

EventTime Src Dst HoldTime

- Physical topology
- capacity: node － CPU 100%, Disk 100%
link － BW 100%, delay(by time or hop count)

- capacity: node － CPU 100%, Disk 100%
- Task graph
- consumption: node － CPU, Disk (by config file)
link BW (by config file)

- consumption: node － CPU, Disk (by config file)

- 預計要做的分析：
- Request hold time
- Disk / CPU / BW consumption
- Topology graph (topology generator, ISP map )
- Task graph (N = 2, 3… or D = 2, 3... )
- number of group
- 其他種方法

0

2

- Metis problem : connectivity

1

0

- Other Group map method:
1. First each node is a group

2. Random choose the smallest group.

9

9

1

1

8

8

7

7

6

6

4

4

5

5

3

3

2

2

0

0

(b)

(a)

3. Then choose the smaller group which it connect to

4. Repeat the step 2 until reach your goal. (group number)

9

9

1

1

8

8

7

7

6

6

4

4

5

5

3

3

2

2

0

0

(b)

(c)

9

9

1

1

8

8

7

7

6

6

4

4

5

5

3

3

2

2

0

0

(f)

(e)

4

2

3

5

2

4

Dst

2

4

5

1

3

3

1

5

2

2

1

3

2

0

2

2

3

3

3

random choose a node with

upperlink to be the src of group ?

4

Problem solution 1

Grouping according to cut edge

4

2

3

5

2

4

Dst

2

4

5

1

3

3

1

5

2

2

1

3

2

0

2

2

3

3

3

4

Problem solution 2

Built level according to cut edge

2

2

Dst

1

3

3

2

0

- Group method problem
- Performance improvement
- Simulation graph
- Experiment report