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Extra Practice for Sem 2, Quiz 5

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Extra Practice for Sem 2, Quiz 5

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the short leg, so to get

long leg, multiply by √3

hyp, multiply by 2

30

42

21√3

60

21

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have a leg, so the other leg is congruent, and to get the hyp, multiply by √2

45

21√2

21

45

21

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

9√3

30

I have the hyp, so get short leg first by dividing by 2

9

18

60

Then, from the short leg to get the long leg, multiply by √3

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

17√3

2

I have the hyp, so get short leg first by dividing by 2

30

17

2

17

60

Then, from the short leg to get the long leg, multiply by √3

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the hyp, so get short leg first by dividing by 2

7√2

60

Then, from the short leg to get the long leg, multiply by √3

7√6

14√2

30

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the hyp, so get short leg first by dividing by 2

12√3

60

Then, from the short leg to get the long leg, multiply by √3

36

24√3

30

12√3•√3 = 12•3 = 36

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the long leg, so get short leg first by dividing by √3

24

60

Then, from the short leg to get the hyp, multiply by 2

24√3

48

30

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the long leg, so get short leg first by dividing by √3

10√2

60

Then, from the short leg to get the hyp, multiply by 2

10√6

20√2

30

√2

10√6

√3

= 10√2

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the long leg, so get short leg first by dividing by √3

6√3

60

Then, from the short leg to get the hyp, multiply by 2

18

12√3

30

18

√3

• √3

• √3

= 18√3

3

= 6√3

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the long leg, so get short leg first by dividing by √3

40√3

3

30

20

Then, from the short leg to get the hyp, multiply by 2

20

√3

• √3

• √3

= 20√3

3

60

20√3

3

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the hyp, so to get the legs, divide by √2

45

12√10

12√5

√5

12√10

√2

= 12√5

45

12√5

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the hyp, so to get the legs, divide by √2

21√2

21√2

42

√2

• √2

• √2

= 42√2

2

45

45

42

= 21√2

Use special right ∆ rules to solve the triangle. Answers in simplified radical form

I have the hyp, so to get the legs, divide by √2

45

5√7

5√14

2

5√7

√2

• √2

• √2

= 5√14

2

45

5√14

2

Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth.

I have the hyp and the side adjto A, so I will use the cos.

B

23

cosA = 16/23

A = cos-1 (16/23)

A = 45.9

45.9

C

A

16

Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth.

I have the hyp and the side oppto B, so I will use the sin.

B

23

44.1

sinA = 16/23

A = sin-1 (16/23)

A = 44.1

45.9

C

A

16

Check: 44.1 + 45.9 = 90 yes!

Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth.

I have several choices for finding the missing side. I am using the sin of A; I’m looking for adjside, and I have the hyp.

B

23

44.1

sin (45.9) = x

1 23

x = 23sin(45.9)

x = 16.5

16.5

45.9

C

A

16

Check: 16.52 + 162 = 232

528.25 ≈ 529

Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth.

I have the side oppof A, so I will use the sinto find the hyp.

B

139.5

50

sin (21) = 50

1 x

x sin (21) = 50

x = 50

sin (21)

x = 139.5

21

A

C

Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth.

I have the side oppof A, so I will use the tan to find the adjside.

B

139.5

50

tan (21) = 50

1 x

x tan (21) = 50

x = 50

tan (21)

x = 130.3

21

A

130.3

C

Check: 502 + 130.32 = 139.52

19452.04 ≈ 19460.25

Use SohCah Toa, or the Pythagorean Thm, to solve the triangle. Round to the nearest tenth.

B

B = 90 – 21 = 69

139.5

69

50

21

A

130.3

C

Check: sin(69) = 130.3 / 139.5

.9336 ≈ .9341