1 / 5

Problem Set 3 Problem 24

Problem Set 3 Problem 24. By Ellen Dickerson. Problem 24. If the matrix has 1 as an eigenvalue , find another eigenvalue for A. To find the eigenvalues of a 2x2 matrix we do the following 1.) Form the matrix A- λ I

Download Presentation

Problem Set 3 Problem 24

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Problem Set 3 Problem 24 By Ellen Dickerson

  2. Problem 24 If the matrix has 1 as an eigenvalue, find another eigenvalue for A.

  3. To find the eigenvalues of a 2x2 matrix we do the following 1.) Form the matrix A- λI 2.) Solve the equation (a- λ)(d- λ) – bc = 0 for λ by factoring or using the quadratic formula - λ - (t- λ)(2t- λ) – (1)(1-t) =0

  4. (t- λ)(2t- λ) – (1)(1-t) = 0 We know one of the eigenvalues is 1 so we will replace lambda with 1. (t-1)(2t-1) – (1)(1-t) = 0 Now we will solve for t. 2t2 – 3t + 1 – (1 – t) = 0 2t2 – 2t = 0 t(2t - 2) = 0 t = 0 or 2t - 2 = 0 2t = 2 t = 1

  5. Lets say that t = 1 then is equal to So now we will find the eigenvalue for (1- λ)(2- λ) - (1)(0) = 0 λ 2 - 3 λ + 2 = 0 (λ-2)(λ-1) = 0 (λ-2) = 0 or (λ-1) = 0 λ = 2 or λ = 1 We already know 1 is one of the eigenvalues so 2 is another eigenvalue for the matrix.

More Related