7.5 part 1
This presentation is the property of its rightful owner.
Sponsored Links
1 / 13

7.5 part 1 Work and Pumping Liquids PowerPoint PPT Presentation


  • 84 Views
  • Uploaded on
  • Presentation posted in: General

7.5 part 1 Work and Pumping Liquids. Hoover Dam Nevada & Arizona. Hoover Dam Powerhouse Nevada & Arizona. Greg Kelly, Hanford High School, Richland, Washington. a Find k :. b. How much work would be needed to stretch the spring 3m beyond its natural length?. Review: Hooke’s Law:.

Download Presentation

7.5 part 1 Work and Pumping Liquids

An Image/Link below is provided (as is) to download presentation

Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author.While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server.


- - - - - - - - - - - - - - - - - - - - - - - - - - E N D - - - - - - - - - - - - - - - - - - - - - - - - - -

Presentation Transcript


7 5 part 1 work and pumping liquids

7.5 part 1

Work and Pumping Liquids

Hoover Dam

Nevada & Arizona


7 5 part 1 work and pumping liquids

Hoover Dam Powerhouse

Nevada & Arizona

Greg Kelly, Hanford High School, Richland, Washington


7 5 part 1 work and pumping liquids

a Find k:

b

How much work would be needed to stretch the spring 3m beyond its natural length?

Review: Hooke’s Law:

A spring has a natural length of 1m.

A force of 24N stretches the spring to 1.8 m.


7 5 part 1 work and pumping liquids

If we add up all these small bits of work we get:

Over a very short distance, even a non-constant force doesn’t change much, so work becomes:


7 5 part 1 work and pumping liquids

Check:

A leaky 5 lb bucket is raised 20 feet

The rope weighs 0.08 lb/ft.

The bucket starts with 2 gal (16 lb) of water and is empty when it just reaches the top.

Work:

Bucket:

Water:

The force is proportional to

remaining rope.


7 5 part 1 work and pumping liquids

A leaky 5 lb bucket is raised 20 feet

The rope weighs 0.08 lb/ft.

The bucket starts with 2 gal (16 lb) of water and is empty when it just reaches the top.

Work:

Bucket:

Water:


7 5 part 1 work and pumping liquids

Check:

A leaky 5 lb bucket is raised 20 feet

The rope weighs 0.08 lb/ft.

The bucket starts with 2 gal (16 lb) of water and is empty when it just reaches the top.

Work:

Bucket:

Water:

Rope:

Total:


7 5 part 1 work and pumping liquids

4 ft

0

10 ft

dx

10

5 ft

I want to pump the water out of this tank. How much work is done?

5 ft

4 ft

The force is the weight of the water. The water at the bottom of the tank must be moved further than the water at the top.

10 ft

Consider the work to move one “slab” of water:


7 5 part 1 work and pumping liquids

4 ft

0

10 ft

dx

10

5 ft

I want to pump the water out of this tank. How much work is done?

5 ft

4 ft

10 ft

distance

force


7 5 part 1 work and pumping liquids

4 ft

0

A 1 horsepower pump, rated at 550 ft-lb/sec, could empty the tank in just under 14 minutes!

10 ft

dx

10

5 ft

I want to pump the water out of this tank. How much work is done?

5 ft

4 ft

10 ft

distance

force


7 5 part 1 work and pumping liquids

2 ft

10 ft

A conical tank is filled to within 2 ft of the top with salad oil weighing 57 lb/ft3.

How much work is required to pump the oil to the rim?

10 ft

Consider one slice (slab) first:


7 5 part 1 work and pumping liquids

2 ft

10 ft

A conical tank if filled to within 2 ft of the top with salad oil weighing 57 lb/ft3.

How much work is required to pump the oil to the rim?

10 ft


7 5 part 1 work and pumping liquids

2 ft

10 ft

A conical tank if filled to within 2 ft of the top with salad oil weighing 57 lb/ft3.

How much work is required to pump the oil to the rim?

10 ft

p


  • Login