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11.1: The Constant e and Continuous Compound InterestPowerPoint Presentation

11.1: The Constant e and Continuous Compound Interest

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Review (Mat 115)

- Just like π, e is an irrational number which can not be represented exactly by any finite decimal fraction.
- However, it can be approximated by
for a sufficiently large x

e

e

e

Review

- Simple interest: A = P + Prt = P(1 + rt)
- Compound Interest: A = P(1 + r)t
or

with n = 1 (interest is compounded annually

– once per year)

- Other compounding periods:
semiannually(2), quarterly(4), monthly(12),

weekly(52), daily(365), hourly(8760)…

- Continuous Compounding:(see page 589 for the proof)
A = Pert

A: future value

P: principal

r: interest rate

t: number of years

Example 1: Generous Grandma

Your Grandma puts $1,000 in a bank for you, at 5% interest. Calculate the amount after 20 years.

Simple interest:

A = 1000 (1 + 0.0520) = $2,000.00

Compounded annually:

A = 1000 (1 + .05)20 =$2,653.30

Compounded daily:

Compounded continuously:

A = 1000 e(.05)(20) = $2,718.28

Example 2: IRA

- After graduating from Barnett College, Sam Spartan landed a great job with Springettsbury Manufacturing, Inc. His first year he bought a $3,000 Roth IRA and invested it in a stock sensitive mutual fund that grows at 12% a year, compounded continuously. He plans to retire in 35 years.
- What will be its value at the end of the time period?
- A = Pert = 3000 e(.12)(35) =$200,058.99
- The second year he repeated the purchase of an identical Roth IRA. What will be its value in 34 years?
- A = Pert = 3000 e(.12)(34) =$177,436.41

Example 3

What amount (to the nearest cent) will an account have

after 5 years if $100 is invested at an annual nominal rate

of 8% compounded annually? Semiannually? continuously?

- Compounded annually
- Compounded semiannually
- Compounded continuously
A = Pert = 100e(.08*5)

= 149.18

If $5000 is invested in a Union Savings Bank 4-year CD that earns 5.61% compounded continuously, graph the amount in the account relative to time for a period of 4 years.

Example 4- Use your graphing calculator:
- Press y=
- Type in 5000e^(x*0.0561)
- Press ZOOM, scroll down, then press ZoomFit
- You will see the graph
- To find out the amount after 4 years
- Press 2ND, TRACE, 1:VALUE
- Then type in 4, ENTER

How long will it take an investment of $10000 that earns 5.61% compounded continuously, graph the amount in the account relative to time for a period of 4 years.

to grow to $15000 if it is invested at 9% compounded

continuously?

Formula: A =P ert

15000 = 10000 e .09t

1.5 = e .09t

Ln (1.5) = ln (e .09t)

Ln (1.5) = .09 t

So t = ln(1.5) / .09

t = 4.51

It will take about 4.51 years

Example 5How long will it take money to triple if it is that earns 5.61% compounded continuously, graph the amount in the account relative to time for a period of 4 years.

invested at 5.5% compounded continuously?

Formula: A =P ert

3P = P e .055t

3 = e .055t

Ln 3 = ln (e .055t)

Ln 3 = .055t

So t = ln3 / .055

t = 19.97

It will take about 19.97 years

Example 6- Review on how to solve exponential equations that involves e if needed (materials in MAT 115)

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