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Doppler Effect Problems. f ’ = f ( V sound +/- V detector )/ ( V sound +/- V source ) Step 1: Identify and label all the variables. Step 2: Solve for the variable you are trying to find. Step 3: V detector is (+) if the detector moves towards the source.

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Doppler effect problems

Doppler Effect Problems

f’ = f (Vsound +/- Vdetector)/ (Vsound +/- Vsource)

Step 1: Identify and label all the variables.

Step 2: Solve for the variable you are trying to find.

Step 3: Vdetectoris (+) if the detector moves towards the source.

Step 4: Vsource is (-) if the source moves towards the detector.

Step 5: Plug N Chug ( with units).

Step 6: Does the answer make sense?


Doppler effect challenge

Doppler Effect Challenge

At a NASCAR race, a speeding car approaches Sally, who is in the stands, at a speed of 40 m/s. Sally gets up to go to the concession stand, and briskly walks at 2 m/s in a direction away from the speeding car. The driver of the car (the source) hears a sound of 2000Hz. What frequency does she perceive?


Doppler effect challenge1

Doppler Effect Challenge

At a NASCAR race, a speeding car approaches Sally, who is in the stands, at a speed of 40 m/s. Sally gets up to go to the concession stand, and briskly walks at 2 m/s in a direction away from the speeding car. The driver of the car (the source) hears a sound of 2000Hz. What frequency does she perceive?

Answer: f’ = 2253Hz


Doppler effect challenge2

Doppler Effect Challenge

The speeding car approaches Sally again. This time Sally perceives a frequency of 2345Hz, while the driver of the car ( the source) hears a sound of 2000 Hz. If Sally is sitting still this time, how quickly is the speeding car approaching Sally?


Doppler effect challenge3

Doppler Effect Challenge

The speeding car approaches Sally again. This time Sally perceives a frequency of 2345Hz, while the driver of the car ( the source) hears a sound of 2000 Hz. If Sally is sitting still this time, how quickly is the speeding car approaching Sally?

Answer: Vsource = 50 m/s


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