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# SOLUTION - PowerPoint PPT Presentation

Solve a multi-step problem. EXAMPLE 4. RENTAL BUSINESS. A business rents in-line skates and bicycles. During one day, the business has a total of 25 rentals and collects \$450 for the rentals. Find the number of pairs of skates rented and the number of bicycles rented.

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EXAMPLE 4

A business rents in-line skates and bicycles. During one day, the business has a total of 25 rentals and collects \$450 for the rentals. Find the number of pairs of skates rented and the number of bicycles rented.

EXAMPLE 4

SOLUTION

STEP1

Write a linear system. Let xbe the number of pairs of skates rented, and let ybe the number of bicycles rented.

x + y =25

Equation for number of rentals

15x + 30y = 450

Equation for money collected from rentals

STEP2

Graph both equations.

The business rented 20 pairs of skates and 5 bicycles.

?

?

15(20) + 30(5) 450

20+525

=

=

450 =450

25 =25

Solve a multi-step problem

EXAMPLE 4

STEP3

Estimate the point of intersection. The two lines appear to intersect at(20, 5).

STEP4

Check whether (20, 5) is a solution.

In Example 4, suppose the business has a total of 20 rentals and collects \$ 420. Find the number of bicycles rented.

6.

Solve a multi-step problem

EXAMPLE 4

for Example 4

GUIDED PRACTICE

SOLUTION

STEP1

Write a linear system. Let xbe the number of pairs of skates rented, and let ybe the number of bicycles rented.

x + y =20

Equation for number of rentals.

15x + 30y = 420

Equation for money collected from rentals.

x+y 20

15x+ 30y 420

=

=

15(12) + 30(8) 420

=

Solve a multi-step problem

EXAMPLE 4

for Example 4

GUIDED PRACTICE

STEP2

Graph both equations.

STEP3

Estimate the point of intersection. The two lines appear to intersect at(12, 8).

STEP4

Check whether (12, 8) is a solution.

12 + 8 = 20

20 = 20

420 = 420

The business rented number of bicycle is 8.

Solve a multi-step problem

EXAMPLE 4

EXAMPLE 4

for Example 4

GUIDED PRACTICE