dx = v x t dy = v y t + ½ at 2. Projectile Motion. Projectile. Object given an initial velocity, that then moves only under the force of gravity. Trajectory. The path that a projectile traces. Parabolic (neglecting the effect of wind resistance).
dx = vxtdy = vyt + ½ at2
Object given an initial velocity, that then moves only under the force of gravity.
The path that a projectile traces. Parabolic (neglecting the effect of wind resistance).
Horizontal and Vertical components of motion are independent of one another, only when they act in concert do we get a true parabolic trajectory.
NOTE: ag = -9.8m/s2
Acceleration in the x direction = 0
Constant velocity in the X direction
(note the constant size of the vector)
Acceleration in the Y direction = -9.8 m/s2
Increase velocity in the Y direction (note the increasing size of vectors)
A stone is thrown horizontally from the top of a cliff which is 44m high at a velocity of 15m/s.
a)How long does it take for the stone to reach the bottom of the cliff?
b)How far from the base of the cliff does the stone strike the ground?
Formulasx = vxty = vyt + ½ at2
Vy = at
= (-9.8 m/s2)(3s)
Vy = -29 m/s
vx2 + vy2 = v2
-292 + 152 = v2
841 + 225 = v2
1066 = v2
V = 33 m/s
15 m/s (given)
*Break v up into vx and vy
A ball is thrown into the air with an initial velocity of 20m/s at an angle of 60º above the horizontal.
a) How long does the ball take to land?
b)How high did the ball fly?
c)What was its range?